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klio [65]
3 years ago
14

Harlon wrote the equation uppercase A = 18 (x squared + 1) to find the area of a rectangle that has a length of x squared + 1 an

d a width of 18. He solved for x and got x = plus-or-minus StartRoot StartFraction uppercase A Over 18 EndFraction minus 1 EndRoot Which of the following is an equivalent equation for x?
Mathematics
1 answer:
Arturiano [62]3 years ago
3 0

Answer:

its A

Step-by-step explanation:

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Written as a simplified polynomial in standard form, what is the result when (3x-1)^2 is subtracted from 4?
nikklg [1K]

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3(x-1)x(3x+1)

Step-by-step explanation:

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Jeremy and his friend spend X dollars on each of 12 movie ticket plus $10 for popcorn how much did they spend in all
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12x+10

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Find the circumference for 5 and 7
Thepotemich [5.8K]

Step-by-step explanation:

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=2π(7)

= 43.98 mm

7) 2πr

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What is the mixed number form<br> of 33/8
goblinko [34]
HCF of 8 that will go as much as possible to 33

4*8=32 and denominator is 8

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4 0
3 years ago
Read 2 more answers
A random sample of 16 one-kilogram sugar packets is obtained and the actual weights of the packets are measured. The sample mean
elena55 [62]

Answer:

The 99% two-sided confidence interval for the average sugar packet weight is between 0.882 kg and 1.224 kg.

Step-by-step explanation:

We are in posession of the sample's standard deviation, so we use the student's t-distribution to find the confidence interval.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 16 - 1 = 15

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 35 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.99}{2} = 0.905([tex]t_{995}). So we have T = 2.9467

The margin of error is:

M = T*s = 2.9467*0.058 = 0.171

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 1.053 - 0.171 = 0.882kg

The upper end of the interval is the sample mean added to M. So it is 1.053 + 0.171 = 1.224 kg.

The 99% two-sided confidence interval for the average sugar packet weight is between 0.882 kg and 1.224 kg.

3 0
3 years ago
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