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Feliz [49]
3 years ago
13

Assume that the weight loss for the first month of a diet program varies between 6 pounds and 12​ pounds, and is spread evenly o

ver the range of​ possibilities, so that there is a uniform distribution. find the probability of the given range of pounds lost. less than 99 pounds
Mathematics
2 answers:
Crank3 years ago
8 0

Answer: 0.5

Step-by-step explanation:

The probability density function for x that uniformly distributed in interval [a,b] :

f(x)=\dfrac{1}{b-a}

We assume that the weight loss for the first month of a diet program varies between 6 pounds and 12​ pounds and is spread evenly over the range of​ possibilities, so that there is a uniform distribution.

Let x be the weight loss for the first month of a diet program.

Density function = f(x)=\dfrac{1}{12-6}=\dfrac{1}{6}

Now , the probability of the given range of pounds lost is less than 9 pounds :

=\int^{12}_{9}\ f(x)\ dx\\\\= \int^{12}_{9}\ \dfrac{1}{6}\ dx\\\\= \dfrac{1}{6}[x]^{12}_{9}\\\\=\dfrac{1}{6}(12-9)=0.5

Hence, the required probability = 0.5

Katena32 [7]3 years ago
6 0

If the distribution is uniform between 6 and 12, the probability of being less than 99 is 1 (certainty).

_____

Perhaps you intend to find the probability that the loss is less than 9 pounds. That value is

... (9 - 6)/(12 - 6) = 3/6 = 1/2

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