Answer: 0.5
Step-by-step explanation:
The probability density function for x that uniformly distributed in interval [a,b] :
We assume that the weight loss for the first month of a diet program varies between 6 pounds and 12 pounds and is spread evenly over the range of possibilities, so that there is a uniform distribution.
Let x be the weight loss for the first month of a diet program.
Density function =
Now , the probability of the given range of pounds lost is less than 9 pounds :
![=\int^{12}_{9}\ f(x)\ dx\\\\= \int^{12}_{9}\ \dfrac{1}{6}\ dx\\\\= \dfrac{1}{6}[x]^{12}_{9}\\\\=\dfrac{1}{6}(12-9)=0.5](https://tex.z-dn.net/?f=%3D%5Cint%5E%7B12%7D_%7B9%7D%5C%20f%28x%29%5C%20dx%5C%5C%5C%5C%3D%20%5Cint%5E%7B12%7D_%7B9%7D%5C%20%5Cdfrac%7B1%7D%7B6%7D%5C%20dx%5C%5C%5C%5C%3D%20%5Cdfrac%7B1%7D%7B6%7D%5Bx%5D%5E%7B12%7D_%7B9%7D%5C%5C%5C%5C%3D%5Cdfrac%7B1%7D%7B6%7D%2812-9%29%3D0.5)
Hence, the required probability = 0.5