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torisob [31]
3 years ago
13

How do I solve this?

Mathematics
1 answer:
umka2103 [35]3 years ago
8 0
The answer would be c
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multiple choice in picture
podryga [215]

Answer:

0.8

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Solve the equation -2 = 3x/5 + 1
kirill [66]

- 2 =  \dfrac{3x}{5}  + 1 | \times 5 \\  - 10 = 3x + 5 \\  - 3x = 15 | \div ( - 3) \\ x =  - 5

4 0
3 years ago
9. Write quadratic function with zeros 3, 6
Dmitry_Shevchenko [17]

Answer:

(x-3)(x-6)

Step-by-step explanation:

do you want an explanation?

7 0
3 years ago
Which coordinate lies in the solution set for
tatyana61 [14]

Answer:

Step-by-step explanation:

to do this, u would just sub ur answer choices into the inequalities and see what is true. Keeping in mind, that ur point has to satisfy both inequalities for it to be a solution.

2x + y < 12...subbing in (3,3)        3x - 2y > 2...subbing in (3,3)

2(3) + 3 < 12                                   3(3) - 2(3) > 2

6 + 3 < 12                                        9 - 6 > 2

9 < 12....true                                       3 > 2....true

(3,3) lies in the solution set <==

7 0
3 years ago
Find the slope of the line tangent to the
g100num [7]
Ln(xy) - 2x =0

slope of the tangent line = derivative of the function

[ln(xy)]' = [2x]'

[1/(xy)] [y + xy'] = 2

y + xy' = 2(xy)

xy' = 2xy - y =y(2x-1)

y' = y(2x-1)/x

Now use x = -1 to find y and after to find y'

ln(xy) = 2x
x=-1
ln(-y) =-2

-y = e^-2

y = - e^-2

y' = [-e^-2][2(-1)-1]/(-1) = [e^-2](-2-1)= [e^-2](-3) = - 3e^-2

Answer: option 6. from the list
8 0
3 years ago
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