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3 years ago

I need help!

Mathematics

1 answer:

pashok25 [27]3 years ago

6 0

Answer:

No idea sorry we have not learned this yet

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Solve for y:y= [-7-6]<br><br>answers:<br> (a)-13 (b)13 (c)1 (d) -1 (e) none of these

Natali [406]

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Hi my lil bunny!

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$y= [-7-6]$

$y = -13$

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Have a great day/night!

❀*May*❀

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3 years ago

Rename the number 650 in tens

Ad libitum [116K]

Answer (quite straightforward):

650

= 65 x 10

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2 years ago

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A linear relationship has the point (4, 48) and its rate of change is 12.

Triss [41]

Answer:

Step-by-step explanation:

Y-48=12(x-4)

Y= 12x

So the y intercept is 0

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2 years ago

Every point on the perpendicular bisector of a segment is?

lisov135 [29]

Its equally distant from the endpoints of the segment to find the center of the following rotation

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3 years ago

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The perimeter of a rectangle is 150 cm. the length is 4 cm greater than the width find the width and length

Fudgin [204]

Let's call the width of our rectangle $w$ and the length $l$ . We can say $l = w + 4$ , since the length is equal to 4 cm greater than the width.

Also remember that the perimeter of a rectangle is the sum of two times the width and two times the length, or $P = 2l + 2w$ . To solve this problem, we can substitute in the information we know, as shown below:

$150 = 2(w + 4) + 2w$

$150 = 4w + 8$

$142 = 4w$

$w = \frac{71}{2}$

Now, we can substitute in the width we found into the formula for length, which is $l = w + 4$ :

$l = \frac{71}{2} + 4$

$l = \frac{79}{2}$

The width of our rectangle is $\boxed{\frac{71}{2} \,\, \textrm{cm}}$ cm and the length of our rectangle is $\boxed{\frac{79}{2} \,\, \textrm{cm}}$

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2 years ago