Answer & Step-by-step explanation:
Null hypothesis (H0): μ=100 lbs
Alternative hypothesis (H1): μ>100 lbs
<em>We must use the t-student distribution because the population standard deviation is unknown.</em>
t-statistic formula:
t= (xbar-m)/(S/(sqrt(n)))
xbar: sample mean
m: hypothesized value
S: sample standard deviation
n: number of observations
t=(104-100)/(10/sqrt(25))
t-statistic= 2
The critical value from the t-student distribution with, 25-1 degrees of freedom and 1% significance level , is 2.4922
Because the t-statistic is less than the critical value, then you do not reject the null hypothesis. Then there is NO statistical evidence to affirm that the average weight population of product X is greater than 100 lbs.
20 meters per second so 44.7 MPH
Answer:
The bench costs $425
And the Table costs $510
Step-by-step explanation:
table + bench = $ 935
$85 + 2b = $935
$935 - $ 85 = $ 850
$850/ 2 = 425 = b
Now, before we continue, I want to stress the importance of what dy/dt and dx/dt actually mean.
When we're dealing with time, space, and movement along a one-directional plane, we're moving with two scalar quantities (using our parametric representation of a particle), namely its x-direction and its y-direction.
Thus, by differentiating x with respect to t, we're literally saying: "well, what is the change of rate of x in relation to time", or "as t moves along the plane, what is the change of rate of x in that time?"
This can be stressed for the y-ordinate, as well.
So, the change of rate of the y-ordinate (dy/dt is 4cm/s). This is how fast the vertical quantity is changing as time changes at that point.