Answer:
hi there ☺️
Here we will use algebra to find three consecutive integers whose sum is 345. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 345. Therefore, you can write the equation as follows:
(X) + (X + 1) + (X + 2) = 345
To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:
X + X + 1 + X + 2 = 345
3X + 3 = 345
3X + 3 - 3 = 345 - 3
3X = 342
3X/3 = 342/3
X = 114
Which means that the first number is 114, the second number is 114 + 1 and the third number is 114 + 2. Therefore, three consecutive integers that add up to 345 are 114, 115, and 116.
114 + 115 + 116 = 345
We know our answer is correct because 114 + 115 + 116 equals 345 as displayed above.
Step-by-step explanation:
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Yes because without a y-intercept it goes through 0. and can you explain the next part?
Answer:
In 2011, 44,500 units are produced
Step-by-step explanation:
Let
t ----> the number of years after 2005
f(t) ----> the number of units produced by a company
we have
f(6)=44,500
so
For t=6, f(t)=44,500
That means
The number of units produced by a company is equal to 44,500 units six years after 2005
so
six years after 2005 is the year 2011
therefore
In 2011, 44,500 units are produced
