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EastWind [94]
3 years ago
5

Sorry for my laziness I kinda didn’t pay attention well I did but I was confused the whole time just please someone ANSWER OR JU

ST HELPPP

Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
7 0
What do you need help with?!
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M2 -2mn + n2 = 4 - (-16) + 16 = 20 + 16 = 36 Have a nice days.......
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A model of a house has been drawn on a coordinate grid. One corner of the house has
sp2606 [1]

Answer:

Point(9,1)

Step-by-step explanation:

Given

Point: (6,3)

Required

Translate 2 units down and 3 units left

Taking the translation 1 after other

When a function is translated down, only the y axis is affected;

2 units down implies that, 2 be subtracted from the y value.

The function becomes

Point: (6, 3 - 2)

Point: (6, 1)

3 units right implies that, 3 be added tothe x value.

The function becomes

Point(3+6,1)

Point(9,1)

Hence;

Option D answers the question

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3 years ago
60 as a product of its prime factors<br>​
viva [34]
2.3.5 = 60 are the prime factors in ascending order , give us a like if I helped :)
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3 years ago
Here, Help meh please
lakkis [162]

Answer:

30 goes in the blank.

Step-by-step explanation:

hope this helps :)

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8 0
2 years ago
Honors Geometry QUiz- Please Help
viktelen [127]

Answer:

QUESTION 2:

The area of the polygon is 21.5 units²

QUESTION 3:

The area of the combined figure is 12 + 18.25·π units²

QUESTION 4:

The area of the figure is 40 units²

QUESTION 5

The area of the compost shape is 40 in.²

Step-by-step explanation:

QUESTION 2.

The area of the polygon is given as follows;

The area of two triangles + The area of trapezoid

1/2×6×3 + 1/2×3×4 + 1/2×(6 + 7) = 21.5 units²

QUESTION 3

The diameter of the semicircle, 'd', is given as follows;

d = √(8² + 3²) = √73

The area of the semicircle = π·d²/4 = π·73/4 = 18.25·π unit²

The area of the right triangle beside the semicircle is given as follows;

1/2 × 8 × 3 = 12 unit²

The area of the combined figure = The area of the semicircle + The area of the right triangle

∴ The area of the combined figure = 12 + 18.25·π units²

QUESTION 4:

The dimensions of the parallelogram are;

Width, W = √(4² + 1²) = √(17)

Length, L = √(8² + 2²) = √(68)

The area of the parallelogram, A_R = W × L = √(17) × √(68) = √(17 × 68) = 34

The area of the parallelogram, A_R = 34 units²

The length of a parallel side, 'A', of the parallelogram is A = 6

The height of the parallelogram, is h = 1

The area of the parallelogram is A = B·h = 6 × 1 = 6 units²

The area of the figure is the sum of the area of the rectangle and the area of the parallelogram

Therefore, we have;

The area of the figure = 34 units² + 6 units² = 40 units²

QUESTION 5

The composite shape consists of a triangle and a rectangle

Therefore, we have;

The area of the rectangle = 5 in. × 7 in. = 35 in.²

The area of the triangle = 1/2 × 2 in. × 5 in. = 5 in.²

The area of the compost shape = The area of the rectangle + The area of the triangle

∴ The area of the compost shape = 35 in.² + 5 in.² = 40 in.²

The area of the compost shape = 40 in.².

5 0
3 years ago
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