Question

Help to solve: if x-2y=0 and -2x+y=2, then 3x-3y=

Answer 1

First equation is $x-2y=0$

Second equation is $-2x+y=2$

subtract equation (2) from (1),

$(x-2y)-(-2x+y)=0-2$

Distribute minus inside the paranthesis,

$x-2y+2x-y=-2$

Now combine the like terms,

$x+2x-2y-y=-2$

$3x-3y=-2$

Thus the value of $3x-3y$ is $-2.$