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Evgesh-ka [11]
3 years ago
12

-2x2+x+8=0 use the quadratic formula to solve the equation

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
5 0
X = -1 is the answer to -2x2+x+8=0
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-5, 20, -80, 320, ... is a geometric sequence a. Find the common ratio, b. Write its recursive rule c. Write its explicit rule.W
mario62 [17]

a.

In order to find the common ratio, we just need to divide a term by the term that comes before it.

So using the terms 20 and -5, we have:

\text{ratio}=\frac{20}{-5}=-4

b.

The recursive rule can be found with the formula:

a_n=a_{n-1}\cdot q

Where an is the nth term and q is the ratio. So we have:

a_n=a_{n-1}\cdot(-4)

c.

The explicit rule can be written as:

a_n=a_1\cdot q^{n-1}

Where an is the nth term, a1 is the first term and q is the ratio. So:

a_n=-5\cdot(-4)^{n-1}

5 0
11 months ago
In quadrilateral ABCD, m∢A = 80, m∢B = 2x, m∢C = x, and m∢D=4x. Find x.
valkas [14]

36 degree :

Step-by-step explanation:

if the value of angleA= x , angleB=2x , angle C=3x and angle D=4x . the value of x is 36 degree

3 0
2 years ago
Would appreciate the help ! ​
aleksandr82 [10.1K]

This is one pathway to prove the identity.

Part 1

\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{1}{\tan(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\cot(\theta) = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{\cos(\theta)}{\sin(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)*\sin(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)(1-\cos(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\

Part 2

\frac{\sin^2(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)-\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-(\cos(\theta)-\cos^2(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-\cos(\theta)+\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\

Part 3

\frac{\sin^2(\theta)+\cos^2(\theta)-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1}{\sin(\theta)} = \frac{1}{\sin(\theta)} \ \ {\checkmark}\\\\

As the steps above show, the goal is to get both sides be the same identical expression. You should only work with one side to transform it into the other. In this case, the left side transforms while the right side stays fixed the entire time. The general rule is that you should convert the more complicated expression into a simpler form.

We use other previously established or proven trig identities to work through the steps. For example, I used the pythagorean identity \sin^2(\theta)+\cos^2(\theta) = 1 in the second to last step. I broke the steps into three parts to hopefully make it more manageable.

3 0
2 years ago
Given these two data sets, IQ-GPA and IQ-SAT, how would you predict Justin’s SAT score based on his GPA? Explain.
BlackZzzverrR [31]
<span>First, use the equation of the trend line to find the IQ that is expected by the GPA. Next, use the other equation of the trend line to find the SAT that is predicted by the IQ.</span>
4 0
3 years ago
Read 2 more answers
What is the range of the given function?
Paladinen [302]

{x | x = –5, 1, 4, 6}  

8 0
3 years ago
Read 2 more answers
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