Question

In the diagram below, angle BAC = 34°.

Answer 1

Answer:

a) 90°

b) 56°

Step-by-step explanation:

If we connect O with B to get two isosceles triangles: ΔAOB and ΔBOC

∠BOC= is central angle ans is twice as ∠BAC, so equals to 2*34°= 68°

Then ∠BCA= (180°- 68°)/2= 56°

∠ABC= ∠ABO+∠CBO= 34°+56°= 90°