In the diagram below, angle BAC = 34°.
1 answer:
Answer:
a) 90°
b) 56°
Step-by-step explanation:
If we connect O with B to get two isosceles triangles: ΔAOB and ΔBOC
∠BOC= is central angle ans is twice as ∠BAC, so equals to 2*34°= 68°
Then ∠BCA= (180°- 68°)/2= 56°
∠ABC= ∠ABO+∠CBO= 34°+56°= 90°
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