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3 years ago

The pair of figures are simular.find the value of each variable

Mathematics

1 answer:

kkurt [141]3 years ago

5 0

Y=12 because the triangles have proportional side lengths

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What is the ratio of 5 turtles and 3 seals

lapo4ka [179]

Answer: 5:3

Step-by-step explanation:

Because there are five turtles and three seals which would mean it would be 5:3

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3 years ago

the area of square field is 5184 square meter find the area rectangular Field whose perimeter is equal to the perimeter of squar

Vikki [24]

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2 years ago

Find the slope given the points (3,18) and (0,18).

docker41 [41]

Answer:

Step-by-step explanation:

Slope is calculated y2-y1/x2-x1

18-18/0-3

0/-3

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3 years ago

A wallet is originally $11.00. With a 40% discount, what is the sales price? Show your work.

NeX [460]

Answer:

$6.6

Step-by-step explanation:

you want to find out what 40% of the original price is ($11)

100% = 11

10%= 1.1

to get 40% you times it by 4

40%= 4.4

you then have to take away the sale reduction from the original

11- 4.4 =$6.6

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%28%7B%20%7Bx%7D%5E%7B2%7D%20%20-%204%7D%29%5E%7B5%7D%20%28%20%7B4x%20-%205%7D%29%5E%7B4%7D

Makovka662 [10]

Let $u=x^2-4$ and $v=4x-5$ . By the product rule,

$\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=\dfrac{\mathrm d(u^5)}{\mathrm dx}v^4+u^5\dfrac{\mathrm d(v^4)}{\mathrm dx}$

By the power rule, we have $(u^5)'=5u^4$ and $(v^4)'=4v^3$ , but $u,v$ are functions of $x$ , so we also need to apply the chain rule:

$\dfrac{\mathrm d(u^5)}{\mathrm dx}=5u^4\dfrac{\mathrm du}{\mathrm dx}$

$\dfrac{\mathrm d(v^4)}{\mathrm dx}=4v^3\dfrac{\mathrm dv}{\mathrm dx}$

and we have

$\dfrac{\mathrm du}{\mathrm dx}=2x$

$\dfrac{\mathrm dv}{\mathrm dx}=4$

So we end up with

$\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=10xu^4v^4+16u^5v^3$

Replace $u,v$ to get everything in terms of $x$ :

$\dfrac{\mathrm d((x^2-4)^5(4x-5)^4)}{\mathrm dx}=10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3$

We can simplify this by factoring:

$10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3=2(x^2-4)^4(4x-5)^3\bigg(5x(4x-5)+8(x^2-4)\bigg)$

$=2(x^2-4)^4(4x-5)^3(28x^2-57)$

7 0

3 years ago