A boy sits for 15 maths exams during the year and gains an average of 1.". He sits for one
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For this case we must find the solution set of the given inequalities:
Inequality 1:
Applying distributive property on the left side of inequality:
Subtracting 3 from both sides of the inequality:
Dividing by 6 on both sides of the inequality:
Thus, the solution is given by all the values of "x" greater than 3.
Inequality 2:
Subtracting 3x from both sides of the inequality:
Subtracting 3 from both sides of the inequality:
Thus, the solution is given by all values of x less than 4.
The solution set is given by the union of the two solutions, that is, all real numbers.
Answer:
All real numbers
First write the inequality: 15
4.75x +3.50
Then to solve, first subtract 3.50 from both sides to get:
11.504.75x
Then divide by 4.75 to get 2.42, and since you can't buy .42 of a bag of fruit, you round down. So your final answer would be 2 bags of fruit.
Then to solve, first subtract 3.50 from both sides to get:
11.50
Then divide by 4.75 to get 2.42, and since you can't buy .42 of a bag of fruit, you round down. So your final answer would be 2 bags of fruit.