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3 years ago

1. Consider the following system of equations.

Mathematics

1 answer:

Ivenika [448]3 years ago

7 0

Answer:

x + 5 = 5

Step-by-step explanation:

Solution doesn't change as the x in the equation is 0 and the answer totals as 5 due to 5 plus 0 being 5

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Round 9,675,599 to the nearest 1,000.

BARSIC [14]

Answer: 9,676,000

Step-by-step explanation:

Increase the digit by 1 if the previous digit is 5 or above

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2 years ago

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Leo bought a car for x dollars one year later the value of the car was 0.88x.which exspression is another way to describe the ch

Furkat [3]

Well, the car depreciated in value by 12%, so you could say
x-12%, or just
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4 years ago

Activity 1.1 Simplify Me Simplify by removing perfect nth powers: 1. √20 2. √300 3. √128 3 4. √ 5 3 5. √50 3

LekaFEV [45]

Answer:

$(a)\ \sqrt{20}=2\sqrt{5}$

$(b)\ \sqrt{300} = 10 \sqrt{3}$

$(c)\ \sqrt{128} = 8 \sqrt{2}$

Step-by-step explanation:

Required

Simplify

$(a)\ \sqrt{20}$

Express 20 as 4 * 5

$\sqrt{20}=\sqrt{4 * 5}$

Split

$\sqrt{20}=\sqrt{4} * \sqrt{5}$

This gives:

$\sqrt{20}=2 * \sqrt{5}$

$\sqrt{20}=2\sqrt{5}$

$(b)\ \sqrt{300$

Express as 100 * 3

$\sqrt{300} = \sqrt{100} * \sqrt{3}$

This gives:

$\sqrt{300} = 10 * \sqrt{3}$

$\sqrt{300} = 10 \sqrt{3}$

$(c)\ \sqrt{128}$

Express as 64 * 2

$\sqrt{128} = \sqrt{64*2}$

Split

$\sqrt{128} = \sqrt{64} * \sqrt{2}$

$\sqrt{128} = 8 * \sqrt{2}$

$\sqrt{128} = 8 \sqrt{2}$

Questions 4 and 5 are not clear

Follow the steps in 1 - 3 to solve 4 and 5

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3 years ago

PLEASE HELP WILL MARK BRAINLIEST

inn [45]

Answer:

First one: Rotation

Second one: Translation

Third one: Reflection

Fourth one: Translation

Step-by-step explanation:

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3 years ago

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write the equation of a line in any form that is parallel 2y = 4x + 8 through the point of (1,3) plz and thank you

V125BC [204]

Answer:

y = 2x+1

Step-by-step explanation:

$2y =4x+8\\\\ Write \:in \: y =mx+b \:form\\\\\frac{2y}{2} = \frac{4x}{2} +\frac{8}{2} \\\\y =2x +4\\m =2\\(1,3) =(x_1,y_1)\\Substitute\:values\:into\:point-slope\:form\\\\y-y_1=m(x-x_1)\\y-3=2(x-1)\\y-3 = 2x-2\\y=2x-2+3\\y =2x+1$

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3 years ago

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