$n-5\cdot\dfrac{2}{3}=\dfrac{3}{4}\\\\n-\dfrac{10}{3}=\dfrac{3}{4}\ \ \ \ |\cdot12\\\\12n-12\cdot\dfrac{10}{3}=12\cdot\dfrac{3}{4}\\\\12n-4\cdot10=3\cdot3\\\\12n-40=9\ \ \ \ |+40\\\\12n=49\ \ \ \ \ |:12\\\\n=\dfrac{49}{12}$

5 0

3 years ago

Resta -7/10 -(-4/15)

Snezhnost [94]

Answer:

-13/30

Step-by-step explanation:

I used KCC. It is a method when you keep you 1st # the same, change subtraction to addition and then change the last # to its opposite. So after KCC, the equation would be -7/10 + 4/15

6 0

3 years ago

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A circular plate has a crack along the line AB, as shown below: A circular plate is shown. The center of the plate is labeled as

makkiz [27]

Well, since point A represents the center, and B represents a point on the outer line of the circle, segment AB would represent the radius, since the radius represents the length from the center to the outside of a circle

Hope this helps

8 0

3 years ago

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