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bearhunter [10]
3 years ago
12

if there is a 4 smiley faces in pattern 1 and 6 smiley faces in pattern 2 and 8 smiley faces in pattern 3 how many smiley faces

will be in pattern 88
Mathematics
2 answers:
miss Akunina [59]3 years ago
6 0

Answer:

Step-by-step explanation:

We technically can't tell! Just because a pattern (increasing by two faces for every new pattern) is true at first doesn't mean it holds forever. However, if we make the assumption that the number of smiley faces continues to increase by 2, we have 4+87*2=177 as the answer, since we start with four and continue through a total of 87 more patterns, each of which adds two more faces.

mixer [17]3 years ago
4 0
We technically can't tell! Just because a pattern (increasing by two faces for every new pattern) is true at first doesn't mean it holds forever. However, if we make the assumption that the number of smiley faces continues to increase by 2, we have 4+87*2=177 as the answer, since we start with four and continue through a total of 87 more patterns, each of which adds two more faces.
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Evaluate the following double integral: xy dA D where the region D is the triangular region whose vertices are (0, 0), (0, 3), (
natulia [17]

Answer:

I= 84

Step-by-step explanation:

for

I=\int\limits^{}_{} \int\limits^{}_D {x*y}  \, dA =  \int\limits^{}_{} \int\limits^{}_D {x*y}  \, dx*dy

since D is the rectangle such that 0<x<3 , 0<y<3

I=\int\limits^{}_{} \int\limits^{}_D {x*y}  \, dA =  \int\limits^{3}_{0} \int\limits^{3}_{0} {x*y}  \, dx*dy =  \int\limits^{3}_{0} {x}  \, dx\int\limits^{3}_{0} {y}  \, dy  = x^{2} /2*y^{2} /2 =  (3^{2} /2 - 0^{2} /2)* (3^{2} /2 - 0^{2} /2) = 3^{4} /4 = 81/4

4 0
3 years ago
The next number in series 7,9,13,29 is:​
Alex17521 [72]

Answer:

285

Step-by-step explanation:

9 = 7 + 2¹

13 = 9 + 2²

29 = 13 + 2⁴

285 = 29 + 2⁸

4 0
3 years ago
One the day a child's birth, a parent deposite 30,000 in a trust fund that pays 5 percent interest, compounded continuously. Det
Ratling [72]

Answer:

  $104,710.29

Step-by-step explanation:

The amount is given by ...

  A = Pe^(rt)

where P is the principal invested at annual rate r for t years. Filling in the numbers, we get ...

  A = 30000e^(.05·25) = 30000e^1.25 ≈ 104,710.29

The balance will be about $104,710.29 on the child's 25th birthday.

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What does (0.6) squired 2 equal
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2 years ago
A, b, c and d are positive integers, such that a+b+ ab = 76, c+d+ cd = 54. Find (a+b+c+d)·a·b·c·d.
lutik1710 [3]

Notice that

(1 + <em>x</em>)(1 + <em>y</em>) = 1 + <em>x</em> + <em>y</em> + <em>x y</em>

So we can add 1 to both sides of both equations, and we use the property above to get

<em>a</em> + <em>b</em> + <em>a b</em> = 76  ==>  (1 + <em>a</em>)(1 + <em>b</em>) = 77

and

<em>c</em> + <em>d</em> + <em>c d</em> = 54  ==>  (1 + <em>c</em>)(1 + <em>d</em>) = 55

Now, 77 = 7*11 and 55 = 5*11, so we get

<em>a</em> + 1 = 7  ==>  <em>a</em> = 6

<em>b</em> + 1 = 11  ==>  <em>b</em> = 10

(or the other way around, since the given relations are symmetric)

and

<em>c</em> + 1 = 5  ==>  <em>c</em> = 4

<em>d</em> + 1 = 11  ==>  <em>d</em> = 10

Now substitute these values into the desired quantity:

(<em>a</em> + <em>b</em> + <em>c</em> + <em>d</em>) <em>a</em> <em>b</em> <em>c</em> <em>d</em> = 72,000

6 0
3 years ago
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