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bearhunter [10]
3 years ago
12

if there is a 4 smiley faces in pattern 1 and 6 smiley faces in pattern 2 and 8 smiley faces in pattern 3 how many smiley faces

will be in pattern 88
Mathematics
2 answers:
miss Akunina [59]3 years ago
6 0

Answer:

Step-by-step explanation:

We technically can't tell! Just because a pattern (increasing by two faces for every new pattern) is true at first doesn't mean it holds forever. However, if we make the assumption that the number of smiley faces continues to increase by 2, we have 4+87*2=177 as the answer, since we start with four and continue through a total of 87 more patterns, each of which adds two more faces.

mixer [17]3 years ago
4 0
We technically can't tell! Just because a pattern (increasing by two faces for every new pattern) is true at first doesn't mean it holds forever. However, if we make the assumption that the number of smiley faces continues to increase by 2, we have 4+87*2=177 as the answer, since we start with four and continue through a total of 87 more patterns, each of which adds two more faces.
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Answer:

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Step-by-step explanation:

Let suppose the attached histogram

a) Total members whose weight 110 = 5

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The measures of spread include the range, quartiles and the interquartile range, variance and standard deviation. Let's consider each one by one.

<u>Interquartile Range: </u>

Given the Data -> First Quartile = 2, Third Quartile = 5

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<u>Range:</u> 8 - 1 = 7

<u>Variance: </u>

We start by determining the mean,

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Solving for the sum of squares is a long process, so I will skip over that portion and go right into solving for the variance.

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5.3

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We take the square root of the variance,

\sqrt{5.28571} = 2.29906

2.3

If you are not familiar with variance and standard deviation, just leave it.

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