Answer: -7twice
Step-by-step explanation:
This is a question on root of quadratic equation. The interpretation of the question
x² 14x + 49 is
x² + 14x + 49 = 0.meaning that we are to find two possible values for x that will make the expression equal 0.
We can use any of the methods earlier taught. For the purpose of this class, I am using factorization methods
x² + 14x + 49 = 0
Now, find the product of the first and the last terms, is
x² × 49 = 49ײ
Now find two terms such that their productbis 49x² and their sum equals 14x, the one in the middle.
We have several factors of 49x² but only one will give sum of 14x. Because of the time, I will only go straight to the required factors .
49x² = 7x × 7x and the sum gives 14x the middle terms..
Now we now replace the middle one by the factors and then factorize by grouping.
x² + 14x + 49 = 0
x² + 7x + 7x + 49 = 0
x(x + 7) + 7(x + 7) = 0
(x + 7)(x + 7). = 0
Now to find this value of x,
x + 7 = 0
x. = -7twice.
The root of the equation = -7twice.
Answer:
y < 1 and y <u>></u> x
Step-by-step explanation:
Let's find each equation without any inequalities first.
We have a dotted line at y = 1
Now, a dotted line represents exclusivity, and hence; it should not include the = sign
Therefore, the answer is y < 1 and y <u>></u> x
Answer
f(6) = -33 and g(-3) = -52
Explanation;
Given the function
f(x)=-5x-3
f(6)=-5(6)-3
f(6) = -30 -3
f(6) = -33
Similarly if g(x)=2x^3+2
g(-3)=2(-3)^3+2
g(-3) = 2(-27)+ 2
g(-3) = -54 + 2
g(-3) = -52
Hence f(6) = -33 and g(-3) = -52
Subtract 612 from 8.7 to get 603.3 :)
