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2 years ago

Find the perimeter of ABC with vertices A (1,-6), B (1,-3), and C (-4,-6).

Mathematics

1 answer:

Crazy boy [7]2 years ago

5 0

Answer:

$p = 8 + \sqrt{34} = 13.83095...$

Step-by-step explanation:

we can easily calculate the perimeter of three points, using vectors. See the picture...

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2 years ago

Nadine and Calvin are simplifying the expression (StartFraction r Superscript negative 5 Baseline s Superscript negative 3 Basel

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Calvin's first step is to simplify the expression is to apply the quotient of powers to get (r Superscript negative 13 Baseline s Superscript negative 1 Baseline) Superscript negative 4 is the correct step

That is $(\frac{r^{-5}s^{-3}}{r^8s^{-2}})^{-4}=(r^{-13}s^{-1})^{-4}$ Calvin's step is the correct step.Because this is the correct way to do simplify the rational expression. And also because Nadine made a blender mistake in her operations in step

Step-by-step explanation:

Given that Nadine and Calvin are simplifying the expression (StartFraction r Superscript negative 5 Baseline s Superscript negative 3 Baseline Over r Superscript 8 Baseline s Superscript negative 2 Baseline EndFraction) Superscript negative 4

Their expression can be written as below

$(\frac{r^{-5}s^{-3}}{r^8s^{-2}})^{-4}$

Nadine's first step is to simplify the expression is to raise the numerator and denominator to the power of 4 to get StartFraction r Superscript negative 20 Baseline s Superscript negative 12 Baseline Over r Superscript 32 Baseline s Superscript 8 Baseline EndFraction

That is $\frac{r^{20}s^{12}}{r^{-32}s^8}$

Calvin's first step is to simplify the expression is to apply the quotient of powers to get (r Superscript negative 13 Baseline s Superscript negative 1 Baseline) Superscript negative 4

That is $r^{-13}s^{-1}$

Now simplify the given expression to check whose step is correct:

$(\frac{r^{-5}s^{-3}}{r^8s^{-2}})^{-4}$

$=(r^{-5}s^{-3}r^{-8}s^{2})^{-4}$ ( using the property $\frac{1}{a^m}=a^{-m}$ )

$=(r^{-5-8}s^{-3+2})^{-4}$

$=(r^{-13}s^{-1})^{-4}$

Therefore $(\frac{r^{-5}s^{-3}}{r^8s^{-2}})^{-4}=(r^{-13}s^{-1})^{-4}$

Therefore Calvin's first step is to simplify the expression is to apply the quotient of powers to get (r Superscript negative 13 Baseline s Superscript negative 1 Baseline) Superscript negative 4 is the correct step.

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