Solution:
The three powers whose value is greater than 500 and less than 550 can be find by following procedure.
We will solve this problem by Hit and trial method by finding the squares, cubes, fourth power, Fifth Power,...etc. of different natural numbers.
23²= 529
8³ = 8 × 8 × 8 =512
The three powers are →→→Eighth power of 2, Square of 23, and Cube of 8.
Answer:
- 
Step-by-step explanation:
Given
f(x) = 
- 
Evaluate f(19) by substituting x = 19 into f(x)
f(19) = 
- 
= 
- 
= 
- 4
= - 
= -
Answer:
correct answer is x = 2.75
Step-by-step explanation:
Given;
AB = 2x-5
BC = 6x
AC = 27
Hence,
=> AC = AB + BC
=> 27 = 2x-5 + 6x
=> 27 = 8x-5
=> 27-5 = 8x
=> 22 = 8x
=> 22/8 = x
=> 11/4 = x
or
2.75 = x
A process or set of rules to be followed in calculations or other problem-solving operations, especially by a computer.
The known endpoint is P = (-16,0)
Let Q = (x,y) be the other endpoint. It is unknown for now.
Looking at the x coordinates of P and Q, we see that they are -16 and x respectively. Adding these values up gives -16+x. Dividing that result by 2 gives (-16+x)/2. This result is exactly equal to the midpoint x coordinate, which is the x coordinate of M (0).
So we have this equation (-16+x)/2 = 0. Let's solve for x
(-16+x)/2 = 0
2*(-16+x)/2 = 2*0
-16+x = 0
x-16 = 0
x-16+16 = 0+16
x = 16
Therefore the x coordinate of point Q is 16.
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Let's do something similar for the y coordinates.
The y coordinates of P and Q are 0 and y respectively. Add them up and divided by 2, then set the result equal to -16 (y coordinate of midpoint M) getting this equation (0+y)/2 = -16
Solve for y
(0+y)/2 = -16
y/2 = -16
2*y/2 = 2*(-16)
y = -32
The y coordinate of point Q is -32
------------------------------------
The point Q goes from (x,y) to (16, -32)
Final Answer: (16, -32)
