Answer:
It is given that in triangle XYZ, XY = 13, YZ=20, and XZ=25.Using the law of cosines, we have
CosC=\frac{a^2+b^2-c^2}{2ab}
cosZ=\frac{(YZ)^2+(XZ)^2-(XY)^2}{2(YZ)(XZ)}
CosZ=\frac{(20)^2+(25)^2-(13)^2}{2(20)(25)}
CosZ=\frac{400+625-169}{1000}
CosZ=\frac{856}{1000}
CosZ=0.856
Z=cos^{-1}(0.856)
Z=37.13^{\circ}
Step-by-step explanation:
Answer:
this is the answer for (03.01 LC)
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Step-by-step explanation:
You have use the Pythagorean Theorem a^{2} + b^{2} = c^{2}
So this is my work
extra notes
- If you didn't know, you cancel exponents with roots.
So the c^{2} is cancled by aka \sqrt{c}
- You can't simplify so it stays like that
Answer: the answer for (03.06 LC)
5
Step-by-step explanation:
In pic
Just look for r after substituting the variables
Hello!
He spends 150 euros so he has 32.66 euros at the end of his trip. To convert it back he does: 1.3687 dollars/1 euro • 32.66 euros = 44.701742 dollars = 44.70 dollars
Answer:18
Step-by-step explanation:2−2+22−4=9
18≠9
Answer:
i think (B) but i am not sure
