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Paladinen [302]
3 years ago
15

Write a program that reads three whole numbers and displays the average of the three number. Sample Run #: java Average3 Interac

tive Session.
1. Enter the first integer: 8
2. Enter the second integer: 10
3. Enter the third integer: 18
The average of 8, 10, and 18 = 12.0.
Computers and Technology
1 answer:
Maksim231197 [3]3 years ago
4 0

Answer:

The program to this question as follows:

Program:

import java.util.*; //import package

class Average //defining class Average

{

public static void main(String[] args) //defining main method

{

int a1,b2,c3;//defining integer variable

float avg; //defining float variable

Scanner obz=new Scanner(System.in); //creating scanner class object

System.out.print("input first number: "); //print message

a1=obz.nextInt(); //input value by user

System.out.print("input second number: "); //print message

b2=obz.nextInt(); //input value by user

System.out.print("input third number: "); //print message

c3=obz.nextInt(); //input value by user

avg=a1+b2+c3/3; //calculating average

System.out.print("The average of "+a1+","+b2+",and "+ c3+"="+ avg);//print value    

}

}

Output:

input first number: 8

input second number: 10

input third number: 18

The average of 8,10,and 18=24.0

Explanation:

In the above code, a class "Average" is defined inside this class the main function is declared in this method three integer variable "a1, b2, and a3" is declared, which input the value from the user side. in this method, a float variable avg is defined that calculates its average value.

  • In the next step, a scanner class object is created, that uses the above integer variable values.  
  • In the "avg" variable add all integer variables then divide its value by 3. At the print, method is used that prints avg variable value.
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jeyben [28]

Answer:

a) 100.75,   103.15,    107.756,    105.536,   106.72

b) 5.06,    8,       14.061,       14.43,    12.89

Explanation:

Measured sample RTT values : 106 ms, 120 ms, 140 ms,  90 ms,  115 ms

First estimated RTT value = 100 ms

∝ = 0.125

β = 0.25

First DevRTT value = 5 ms

<u>A)   Compute the EstimatedRTT after each of these SampleRTT values is obtained,</u>

Formula for estimated RTT = ( 1 - ∝ ) . estimated RTT + ∝.sample RTT

B). <u>Compute  the DevRTT after each sample is obtained,</u>

Formula for DevRTT = ( 1 - β ) . DevRTT + β. | sample RTT - Estimated RTT |

attached below is a detailed solution

5 0
3 years ago
When an object is falling because of gravity, the following formulacan be used to determine the distance the object falls in asp
ser-zykov [4K]

Answer:

True

Explanation:

When an object is falling under the influence of gravity, the distance of fall as a function of time is given by:

D(t)=ut + 1/2 * a * t^2

Where

u = initial velocity of the object ( = 0 in this case as the object is falling only under gravity),

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Simplifying,

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3 years ago
Complete the method, longestWord(), below that takes in an array of Strings and returns the longest String in the array. Note: y
beks73 [17]

Answer:

I am writing a JAVA program.

public class StringMethod {

public static String longestWord(String []words) { //method that takes an array  "word" of strings and returns the longest string in the array word

    int pos = 0; // contains index of the longest word of array words

    int longest = words[0].length(); //initially holds the length of the 1st element of words array

    for(int i=1; i< words.length; i++) { // iterates through each word of the array until the end of array

        if(words[i].length() > longest) { // if the length of word at i-th index of words[] is greater than the length of the word that is contained in longest variable

            pos = i; // assigns the index of the longest array element to pos

            longest = words[i].length();    } } //assigns the word in words[] array with the longest length to longest variable

   return words[pos]; } // returns the longest string in the array    

public static void main(String[] args) { //start of main() function body

String[] animals = {"cat", "horse", "elephant", "bird"}; //creates a String type array named animals which has 4 elements/words

   String longest_word= longestWord(animals); //calls longestWord method to find the longest string in the array animals and assign that longest string to longest_word.

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Explanation:

Suppose we have the array of these elements: "cat", "horse", "elephant", "bird" These are four words in the array. Now lets see how the method longestWord() works:

int pos = 0; This variable is initialized to 0.

int longest = words[0].length();

longest holds the length of element at 0th index of words[] array. length() method is used to return the length of the first element words[0] array.

As the first element of array is "cat" so length of cat is 3. Hence longest = 3

for(int i=1; i< words.length; i++)

The loop has a variable i which is initialized to 1. The loop checks if the value of i is less than length of words[] array. The length of words array is 4 as there are 4 elements i.e. cat, horse, elephant and bird in this array. So the condition evaluates to true because i<words.length i.e. 1<4. The body of the loop will execute now. The body of loop contains an if condition if(words[i].length() > longest) which checks if the length of element of array at i-th index is greater than length of the element that is stored in longest variable. As i=1 so word[i] is word[1] which is the second element of words[] array. The second element is horse.

words[i].length()  means the length of i-th element of words[] array. So this means words[1].length() i.e. the length of element of words[] at 1st index. The length of horse is 5. So the statement if(words[i].length() > longest) is true because longest=3 and words[1].length() = 5 and 5>3. So the statements of if condition will execute now.

pos = i; this variable pos is used to hold the index position of the longest element in array. So pos = 1 as longest element computed so far is "horse".

longest = words[i].length(); This statement then assigns the length of horse to longest. So now the value of longest = 5

At second iteration i is now 2.  Loop condition evaluates to true because i<words.length i.e. 2<4. If condition is also true as i=2 so word[i] is word[2] which is elephant.

words[i].length() now means words[2].length() i.e. the length of element of words[] at 2nd index. The length of elephant is 8. So the statement if(words[i].length() > longest) is true because longest=5 and words[2].length() = 8 and 8>5. So the statements of if condition will execute now.

pos = i; now becomes pos = 2 as longest element computed so far is "elephant".

longest = words[i].length();  This statement then assigns the length of horse to longest. So now the value of longest = 8

At third iteration i is now 3.  The loop again checks if the value of i is less than length of words[] array.The condition evaluates to true because i<words.length i.e. 3<4. The body of the loop will execute now.  if(words[i].length() > longest) checks if the length of element of array at i-th index is greater than length of the element that is stored in longest variable. As i=3 so word[i] is word[3] which is the fourth element of words[] array. The fourth element is bird.

words[i].length() now means words[3].length() i.e. the length of element of words[] at 3rd index. The length of bird is 4. So the statement if(words[i].length() > longest) is false because longest=8 and words[2].length() = 4 and 4<8. So the statements of if condition will not execute now.

At fourth iteration i is now 4.  The loop again checks if the value of i is less than length of words[] array.The condition evaluates to false because i==words.length i.e. 4=4. So the loop breaks.

 return words[pos]; statement returns the index position of longest word in words[] array. pos = 2 So the array element at 2nd index is basically the third element of array words[] i.e. elephant. So the longest string in the array is elephant.

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