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IgorLugansk [536]
3 years ago
11

The decimal number 3 is ___ in binary the 2s column plus the 1s column.

Computers and Technology
1 answer:
baherus [9]3 years ago
6 0

Answer:

The answer is "Option a"

Explanation:

In the given question the correct answer is the option a because when we change decimal number 3 into a binary number, It will give "11". To know its decimal number we add both numbers.

<h3>for example:  </h3>

binary to decimal (11)₂=?

∴ 2¹=2 and 2⁰=1

= 1×2¹+1×2⁰

∵ 1×2+1×1

=2+1

=3

and other options are not correct, that can be described as follows:

In option b, option c, and option d, The computer understands the only binary language, that contains only 0 and 1, and in these options, It contains other value, that's why it is not correct.

 

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8. Given the array String[] words, which already contains 1 or more values, write a block of code which counts and returns the n
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Answer:

Following are the code to this question:

public class Main//defining a class

{

public static void main(String[] arg)//defining main method

{

  String[] words={"Key","day", "Know", "kind"};//defining array of String words

  int x=0;//defining integer variable for count value

  for(int i=0;i<words.length;i++)//defining for loop for count value

  {

 if(words[i].startsWith("k")||words[i].startsWith("K"))//use if block to check word start from k

  x=x+1;//increment the value of x

  }

System.out.print("The number of letters which starts from k is: "+ x);//print value with message

}

}

Output:

The number of letters which starts from k is: 3

Explanation:

In this code, inside the main method an array of String "words" is defined that hold a value, and in the next step an integer variable "x" is defined, which is used to count the letters, which starts from k.

For this, a for loop is used that counts the value and in this an, if block is defined that uses the "startsWith" method to check the value and increment the value of x and at the last, it prints its value.

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