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alex41 [277]
4 years ago
7

Graph the linear equation using intercepts

Mathematics
1 answer:
irina1246 [14]4 years ago
7 0

The x-intercept is when y = 0

while

The y-intercept is when x = 0

So, to find the x-intercepts, set y to 0:

3x - 5(0) = 15

3x = 15

Divide both sides by 3:

x = 5

x-intercept is (5, 0)

Now, for the y-intercept:

3(0) - 5y = 15

-5y = 15

Divide both sides by -5:

y = -3

y-intercept is (0, -3)

Therefore, the x-intercept is (5, 0), and the y-intercept is (0, -3).

Now, lets find the slope using these 2 points on the graph and the rate of change formula, which is:

\frac{y2 - y1}{x2 - x1}

Plug in the intercepts (the order of y's and x's doesn't really matter as long as they're consistent):

\frac{0 + 3}{5 - 0} = \frac{3}{5}

Therefore, the slope is \frac{3}{5}, or rise 3, run 5.

Now, lets graph:

<em>( hope this helps! :) )</em>

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Answer:

10.) y = -5x + 7

12.) y = 3/2x - 8

Step-by-step explanation: Since you have to create a new line that us parallel, the slopes will be equivalent. So the mx value will not change. Now we can plug in the coordinates to find the value of b.

10.)

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therefore...

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In case you want the working out -
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D
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