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Firdavs [7]
3 years ago
11

Help meeeeeeeeeeeeeee

Mathematics
2 answers:
photoshop1234 [79]3 years ago
8 0

Answer:

C find ur x value by solving the simultaneous equations

LekaFEV [45]3 years ago
8 0

Answer:

-2

Step-by-step explanation:

6x+4y=-14. X=-2y+7

—————

3

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Find the thirteenth term of an arithmetic sequence if the first term is 3 and the common difference is 3
lesya692 [45]

Answer:

39

Step-by-step explanation:

Formula for the nth term (an) = a1 + d(n - 1)  where a1 = the first term and d = common difference.

So here the 13th term = 3 + 3(13 - 1)

= 3 + 3*12

= 39  (answer).

8 0
3 years ago
Example: Find the smallest positive integer n so that 8!.n is a<br>perfect square.​
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vkdjdduruyeyetjfdywreytdjgkjfkjgkhkhv;

Step-by-step explanation:

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3 years ago
It order of operations can someone help me
Lemur [1.5K]

Answer:

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Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
A professor has learned that three students in his class of 20 will cheat on the final exam. He decides to focus his attention o
balu736 [363]

Answer:

a

P(X \ge 1) = 0.509

b

P(X  \ge 1) = 0.6807

Step-by-step explanation:

From the question we are told that

   The number of students in the class is  N  =  20  (This is the population )

   The number of student that will cheat is  k =  3

   The number of students that he is focused on is  n  =  4

Generally the probability distribution that defines this question is the  Hyper geometrically distributed because four students are focused on without replacing them in the class (i.e in the generally population) and population contains exactly three student that will cheat.

Generally  probability mass function is mathematically represented as

      P(X = x) =  \frac{^{k}C_x * ^{N-k}C_{n-x}}{^{N}C_n}

Here C stands for combination , hence we will be making use of the combination functionality in our calculators  

Generally the that  he finds at least one of the students cheating when he focus his attention on four randomly chosen students during the exam is mathematically represented as

      P(X \ge 1) =  1 - P(X \le 0)

Here  

   P(X \le 0) =  \frac{ ^{3} C_0 *  ^{20 - 3} C_{4- 0}}{ ^{20}C_4}

   P(X \le 0) =  \frac{ ^{3} C_0 *  ^{17} C_{4}}{ ^{20}C_4}

   P(X \le 0) =  \frac{ 1 *  2380}{ 4845}

    P(X \le 0) =  0.491

Hence

    P(X \ge 1) =  1 - 0.491

     P(X \ge 1) = 0.509

Generally the that  he finds at least one of the students cheating when he focus his attention on six randomly chosen students during the exam is mathematically represented as

    P(X \ge 1) =  1 - P(X \le 0)

   P(X  \ge 1) =1- [  \frac{^{k}C_x * ^{N-k}C_{n-x}}{^{N}C_n}]

Here n =  6

So

    P(X  \ge 1) =1- [  \frac{^{3}C_0 * ^{20 -3}C_{6-0}}{^{20}C_6}]

    P(X  \ge 1) =1- [  \frac{^{3}C_0 * ^{17}C_{6}}{^{20}C_6}]

    P(X  \ge 1) =1- [  \frac{1  *  12376}{38760}]

    P(X  \ge 1) =1- 0.3193

    P(X  \ge 1) = 0.6807

   

5 0
3 years ago
What is a terminating decimal
Furkat [3]
It is a decimal that does not go in forever.
6 0
3 years ago
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