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3 years ago

What is the anwser to this −4(w+1)=−24

Mathematics

2 answers:

e-lub [12.9K]3 years ago

8 0

Answer:

− 4 = − 2 0

Step-by-step explanation:

marshall27 [118]3 years ago

4 0

Answer:

= -7

Divide both sides by the numeric factor on the left side, then solve.

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Solve: 2/x + 3/2x - 1/2 = 2/3

polet [3.4K]

Answer:

Step-by-step explanation:

$\frac{2}{x}+\frac{3}{2x}-\frac{1}{2}=\frac{2}{3}\\multiply ~by~6x\\12+9-3x=4x\\21=4x+3x\\7x=21\\x=21/7=3$

6 0

3 years ago

Use the power rules for exponents to simplify the expression

nikklg [1K]

Using rule 5.
Answer: g^4/h^4

I hope I helped. Look up "Exponent rules" Make a song it'll help you memorize it. Actually, it was how dad taught me when I was 13yrs old :)

3 0

3 years ago

Help solving this math

9966 [12]

Answer:

24 cm²
6400 -1600π ≈ 1373.45 square units

Step-by-step explanation:

1. You can look at this several ways.

It can be considered to be a stack of 1+2+3 = 6 squares that are 2 cm on a side, so have a total area of 6 × (2 cm)² = 24 cm².

You can lop off one of the squares sticking out and put it into the empty corner to form a 6 cm by 4 cm rectangle with an area of (6 cm)(4 cm) = 24 cm².

You can consider it to be a 6 cm square with 3 squares cut out of it that are 2 cm on a side: (6 cm)² -3(2 cm)² = (36 -12) cm² = 24 cm².

2. The shaded area is the difference in areas of a square 80 units on a side and a circle of 40 units radius. If we let d represent the side dimension of the square, then the area formulas are ...

Square area = d²

Circle area = π(d/2)²

So the difference area is ...

shaded area = d² -(π/4)d² = d²(1 -π/4)

For d=80, the shaded area is ...

shaded area = 80²(1 -π/4) = 6400 -1600π ≈ 1373.45 square units

6 0

3 years ago

In a load of laundry, 60% of the socks are white. If there are 25 socks in the load, how many are white?

Firdavs [7]

Well turn 60 into a decimal 0.60 and then multiply by 25 which is 15

remember of in math means multiply

6 0

4 years ago

Read 2 more answers

A recent study focused on the number of times men and women send a WeChat message in a day. The information is summarized next.

Ratling [72]

Answer:

1)Null hypothesis: $\mu_{men}=\mu_{women}$

Alternative hypothesis: $\mu_{men} \neq \mu_{women}$

2) Two critical values are $z_{\alpha/2}=-2.58$ and $z_{1-\alpha/2}=2.58$

3) $z=-2.40$

4) $p_v =2*P(z$

5) Comparing the p value with the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we FAIL to reject the null hypothesis, and a would NOT be a significant difference in the mean number of times men and women send a Twitter message in a day.

Step-by-step explanation:

Data given and notation

$\bar X_{men}=23$ represent the mean for the sample men

$\bar X_{women}=28$ represent the mean for the sample women

$\sigma_{men}=5$ represent the population standard deviation for the sample men

$\sigma_{women}=10$ represent the population standard deviation for the sample women

$n_{men}=25$ sample size for the group men

$n_{women}=30$ sample size for the group women

t would represent the statistic (variable of interest)

$\alpha=0.01$ significance level provided

1）Develop the null and alternative hypotheses for this study?

We need to conduct a hypothesis in order to check if the means for the two groups are different, the system of hypothesis would be:

Null hypothesis: $\mu_{men}=\mu_{women}$

Alternative hypothesis: $\mu_{men} \neq \mu_{women}$

Since we know the population deviations for each group, for this case is better apply a z test to compare means, and the statistic is given by:

$z=\frac{\bar X_{men}-\bar X_{women}}{\sqrt{\frac{\sigma^2_{men}}{n_{men}}+\frac{\sigma^2_{women}}{n_{women}}}}$ (1)

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

2）Determine the critical value(s).

Based on the significance level $\alpha=0.01$ and $\alpha/2=0.005$ we can find the critical values with the normal standard distribution, we are looking for values that accumulates 0.005 of the area on each tail on the normal distribution.

For this case the two values are $z_{\alpha/2}=-2.58$ and $z_{1-\alpha/2}=2.58$

3) Calculate the value of the test statistic for this hypothesis testing.

Since we have all the values we can replace in formula (1) like this:

$z=\frac{23-28}{\sqrt{\frac{5^2}{25}+\frac{10^2}{30}}}}=-2.40$

4）What is the p-value for this hypothesis test?

Since is a bilateral test the p value would be:

$p_v =2*P(z$

5）Based on the p-value, what is your conclusion?

Comparing the p value with the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we FAIL to reject the null hypothesis, and a would NOT be a significant difference in the mean number of times men and women send a Twitter message in a day.

4 0

3 years ago