The answer you are looking for is 5/6
It’s probably most definitely the third one but I really don’t know.
Use these equations when converting polar equations to parametric equations:
We know that 
, so substitute that into both equations for x and y.
Now, replace 
with any variable that you want to represent the parametric equations in. I'll use the standard variable, 
Thus, represented in parametric form is:
Let me know if you need any clarifications, thanks!
~ Padoru
Answer:
y = 2(x-3)^2 - 2
Step-by-step explanation:
y = 2x^2 - 12x + 16
y = 2(x^2 - 6x + 8)
y = 2(x^2 - 6x +8 +1 -1) you "complete the square" by bringing the last term (8) up to "half of the middle co-efficient squared". Middle co-efficient is -6, half is -3, squared is 9. To get from 8 to 9 you must add 1 (+1), but if you add 1 you must subtract 1 (-1) so that you don't change the overall value of inside the bracket
y = 2(x^2 - 6x +9) - 2 (bring the -1 outside of the brackets)
y = 2(x-3)^2 - 2
The answer would be $3 becaus of x = $12 and y = $9. $12 - $9 = $3.
