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3 years ago

What is the value of b?

Mathematics

1 answer:

babymother [125]3 years ago

4 0

Right Angle - 90 Degrees

A+B+C = 180

90+B+51 = 180

141 + B = 180

B = 39

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Please Help. Due Soon!

djyliett [7]

Answer:

yes

Step-by-step explanation:

They are correct because the reciprocal ( flipped or opposite) of -2/5 is 5/-2

5 0

3 years ago

Mrs. Huang operates a soybean farm. She buys many supplies in bulk. Often the bulk products need to be custom mixed before Mrs.

Evgen [1.6K]

To solve this problem, let us first assign variables. Let us say that:

x = volume of 67% herbicide solution

y = volume of 46% herbicide solution

The total volume should be 42 liters therefore:

x + y = 42

x = 42 – y --> 1

The component mass balance on the pure herbicide would be:

0.67 x + 0.46 y = 0.55 (42) --> 2

Substituting equation 1 to 2:

0.67 (42 – y) + 0.46 y = 23.1

28.14 – 0.67 y + 0.46 y = 23.1

- 0.21 y = - 5.04

y = 24 L

Calculating for x using equation 1:

x = 42 – 24

x = 18 L

Therefore we only need 18 L of the 67% herbicide solution.

Answer:

A. 18 L

6 0

4 years ago

Read 2 more answers

Find the coordinates of the midpoint of the line segment ab,where a and b have coordinates a(8.0),b(4.6)

umka2103 [35]

$\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ 8}}\quad ,&{{ 0}})\quad 
% (c,d)
&({{ 4}}\quad ,&{{ 6}})
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)
\\\\\\
\left( \cfrac{4+8}{2}~~,~~\cfrac{6+0}{2} \right)\implies (6~~,~~3)$

4 0

4 years ago

If the estimate of expected population proportion having a desired characteristic based on intuition is 60 percent and the accep

Anika [276]

Answer:

Step-by-step explanation:

Our values are:

N = 100,000 (We assume it)

Proportion is p = 0.6

Margin of error (E) = 0.05

confidence-level (cl) = 0.95

Z-value = 1.96

We need to approach through Proportion,

$n=\frac{ (z_2 * p *q) + ME_2}{ME_2 + z_2 * p * q / N}$

Substituting,

$n = \frac{(1.962*0.6*0.4)+0.052}{0.052 + \frac{1.962 * 0.6 * 0.4}{100000}}$

$n= \frac{(3.841 * 0.24)+0.0025}{0.0025+\frac{3.841*0.24}{100000}}$

$n =\frac{ 0.9243}{0.002509}$

$n= 368$

3 0

3 years ago

Sam is eating a Big Hamburger. The first bite was 20% of the Hamburger, the second bite was 20% of what is left and so every nex

lakkis [162]

The weight of the hamburger is 160g after two bites.

Each bite takes away 20% of the weight of the burger, so we'll divide the initial weight by a percentage to find the weight before the bite.

The starting weight is 160g. Because 20% of the weight was removed from a bite, we'll divide this weight by the percentage of the burger remaining after the bite:

$100 - 20 = 80$

80% of the burger is left after a bite. Convert this fraction into a decimal by dividing by 100:

$80 \div 100 = 0.8$

Divide the initial weight by this decimal:

$160 \div 0.8 = 200$

The weight of the burger before the second bite was 200.

We'll do the same procedure for the first bite. The initial weight is 200, and there is 80% of the burger remaining after the first bite. Because 80% is 0.8 in decimal form, divide 200 by 0.8:

$200 \div 0.8 = 250$

The starting weight of the burger before the bites was 250 grams.

6 0

3 years ago