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spin [16.1K]
3 years ago
11

Sam is eating a Big Hamburger. The first bite was 20% of the Hamburger, the second bite was 20% of what is left and so every nex

t bite is 20% of what is left. a How much did the Hamburger weigh originally, if after the second bite there was 160g of it left?
Mathematics
1 answer:
lakkis [162]3 years ago
6 0
The weight of the hamburger is 160g after two bites.

Each bite takes away 20% of the weight of the burger, so we'll divide the initial weight by a percentage to find the weight before the bite.

The starting weight is 160g. Because 20% of the weight was removed from a bite, we'll divide this weight by the percentage of the burger remaining after the bite:

100 - 20 = 80

80% of the burger is left after a bite. Convert this fraction into a decimal by dividing by 100:

80 \div 100 = 0.8

Divide the initial weight by this decimal:

160 \div 0.8 = 200

The weight of the burger before the second bite was 200.

We'll do the same procedure for the first bite. The initial weight is 200, and there is 80% of the burger remaining after the first bite. Because 80% is 0.8 in decimal form, divide 200 by 0.8:

200 \div 0.8 = 250

The starting weight of the burger before the bites was 250 grams.
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3 years ago
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To get the paint colour you want you mix 2 parts red with 3 parts cream and 1 part blueHow much cream and blue will you need to
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3 years ago
Please Answer <br><br> This is due by tomorrow night and I need help
labwork [276]

Answer:

AY = 16

IY = 9

FG = 30

PA = 24

Step-by-step explanation:

<em>The </em><em>centroid </em><em>of the triangle </em><em>divides each median</em><em> at the ratio </em><em>1: 2</em><em> from </em><em>the base</em>

Let us solve the problem

In Δ AFT

∵ Y is the centroid

∵ AP, TI, and FG are medians

→ By using the rule above

∴ Y divides AP at ratio 1: 2 from the base FT

∴ AY = 2 YP

∵ YP = 8

∴ AY = 2(8)

∴ AY = 16

∵ PA = AY + YP

∴ AP = 16 + 8

∴ AP = 24

∵ Y divides TI at ratio 1: 2 from the base FA

∴ TY = 2 IY

∵ TY = 18

∴ 18 = 2

→ Divide both sides by 2

∴ 9 = IY

∴ IY = 9

∵ Y divides FG at ratio 1:2 from the base AT

∴ FY = 2 YG

∵ FY = 20

∴ 20 = 2 YG

→ Divide both sides by 2

∴ 10 = YG

∴ YG = 10

∵ FG = YG + FY

∴ FG = 10 + 20

∴ FG = 30

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The answer would be 40 days

We achieve this answer by dividing the distance of the trip, 30 miles, by the distance traveled per day, 3/4 miles.

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