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Korvikt [17]
3 years ago
10

A baseball player hit 73 home runs in a season. Of the 73 home​ runs, 25 went to right​ field, 25 went to right center​ field, 8

went to center​ field, 10 went to left center​ field, and 5 went to left field.​
(a) What is the probability that a randomly selected home run was hit to left centerleft center ​field?
(b) Was it unusual for this player to hit a home run to left centerleft center ​field?
Mathematics
1 answer:
Elenna [48]3 years ago
8 0

Answer:

A baseball player hit 73 home runs in a season.

Of the 73 home​ runs, 25 went to right​ field, 25 went to right center​ field, 8 went to center​ field, 10 went to left center​ field, and 5 went to left field.​

(a)  the probability that a randomly selected home run was hit to left center ​field = \frac{10}{73}=0.1369 = 13.69%

(B) Since the probability of an unusual event is 0, it was possible for this player to hit a home run to left center ​field.

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I have this for my math review &amp; i just don't seem to get it...<br>what is (.9x+.8y)^2
elena55 [62]
Can you take the quantity [ x + y ] and square it ?

Can you take the quantity  [ x + 2y ] and square it ?

Then you should have no trouble with the square of (.9x + .8y) .

The square of any binomial (expression with 2 terms) is

(square of the first term)
+ (square of the second term)
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8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bb%5E%7B-2%7D%20%7D%7Bb%5E%7B4%7D%20%7D" id="TexFormula1" title="\frac{b^{-2} }{b^{4}
MAXImum [283]

Answer: \frac{1}{b^6}   or b^{-6}  

Step-by-step explanation:

\frac{b^-2+2}{b^4+2}   Add the exponent two to both sides.  After adding -2 and     2 you get 0 and any number raised to the zero power is one. And 4 plus two is 6

\frac{b^0}{b^6}   = \frac{1}{b^6}

3 0
3 years ago
Harry earns an hourly rate of $15. For each additional hour over 40 hours, he earns 150% percent of his regular hourly rate. Las
irinina [24]

Answer:

51 hours

Step-by-step explanation:

$15 x 40 = $600

$15 x 1.50 = $22.5

$22.5 x 11 = $247.5

$600 + $247.5 = $847.5

40 + 11 = 51 hours

7 0
3 years ago
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Log6 8 + log6 27 as single logarithm
Vsevolod [243]
Log[8/(36*3)] Log[2/27] Hope I really help you !
6 0
2 years ago
K is the midpoint of PQ, P has
Pachacha [2.7K]

Answer:

Coordinates of Q (x_2,y_2) \:are\: \mathbf{(7,16)}

Option D is correct option.

Step-by-step explanation:

We are given:

K is the midpoint of PQ

Coordinates of P = (-9,-4)

Coordinates of K = (-1,6)

We need to find coordinates of Q  (x_2,y_2)

We will use the formula of midpoint: Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

We are given midpoint K and x_1,y_1 the coordinates of P we need to find x_2,y_2 the coordinates of Q.

Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})\\(-1,6)=(\frac{-9+x_2}{2},\frac{-4+y_2}{2})\\

Now, we can write

-1=\frac{-9+x_2}{2}, 6=\frac{-4+y_2}{2}\\Simplifying:\\-2=-9+x_2\:,\: 12=-4+y_2\\-2+9=x_2\:,\: 12+4=+y_2\\x_2=7\:,\:y_2=16

So, we get coordinates of Q (x_2,y_2) \:are\: \mathbf{(7,16)}

Option D is correct option.

6 0
3 years ago
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