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Korvikt [17]
3 years ago
10

A baseball player hit 73 home runs in a season. Of the 73 home​ runs, 25 went to right​ field, 25 went to right center​ field, 8

went to center​ field, 10 went to left center​ field, and 5 went to left field.​
(a) What is the probability that a randomly selected home run was hit to left centerleft center ​field?
(b) Was it unusual for this player to hit a home run to left centerleft center ​field?
Mathematics
1 answer:
Elenna [48]3 years ago
8 0

Answer:

A baseball player hit 73 home runs in a season.

Of the 73 home​ runs, 25 went to right​ field, 25 went to right center​ field, 8 went to center​ field, 10 went to left center​ field, and 5 went to left field.​

(a)  the probability that a randomly selected home run was hit to left center ​field = \frac{10}{73}=0.1369 = 13.69%

(B) Since the probability of an unusual event is 0, it was possible for this player to hit a home run to left center ​field.

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