Question

Find the sum. (2a2 + ab + 2b) + (4a2 − 3ab + 9)

Answer 1

$(2a^2+ab+2b)+(4a^2-3ab+9)\\\\=2a^2+ab+2b+4a^2-3ab+9\\\\=(2a^2+4a^2)+(ab-3ab)+2b+9\\\\=\boxed{6a^2-2ab+2b+9}$

Answer 2

Answer:

The sum is  $6a^2-2ab+2b+9$

Step-by-step explanation:

Given two expression

$(2a^2 + ab + 2b)$ and $(4a^2 − 3ab + 9)$

We have to find the sum of above two expression.

$(2a^2 + ab + 2b)+(4a^2 - 3ab + 9)$

Combining like terms we get

$(2a^2+4a^2)+(ab-3ab)+2b+9$

= $6a^2-2ab+2b+9$

The sum is  $6a^2-2ab+2b+9$