Ones, tens, hundreds,thousands, ten thousands, hundred thousands, millions
The capital formation of the investment function over a given period is the
accumulated capital for the period.
- (a) The capital formation from the end of the second year to the end of the fifth year is approximately <u>298.87</u>.
- (b) The number of years before the capital stock exceeds $100,000 is approximately <u>46.15 years</u>.
Reasons:
(a) The given investment function is presented as follows;

(a) The capital formation is given as follows;

From the end of the second year to the end of the fifth year, we have;
The end of the second year can be taken as the beginning of the third year.
Therefore, for the three years; Year 3, year 4, and year 5, we have;

The capital formation from the end of the second year to the end of the fifth year, C ≈ 298.87
(b) When the capital stock exceeds $100,000, we have;
![\displaystyle \mathbf{\left[1000 \cdot e^{0.1 \cdot t}} + C \right]^t_0} = 100,000](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%20%5Cmathbf%7B%5Cleft%5B1000%20%5Ccdot%20%20e%5E%7B0.1%20%5Ccdot%20t%7D%7D%20%2B%20C%20%5Cright%5D%5Et_0%7D%20%3D%20100%2C000)
Which gives;




The number of years before the capital stock exceeds $100,000 ≈ <u>46.15 years</u>.
Learn more investment function here:
brainly.com/question/25300925
as per as I can think the answet will be 38
please give me brainliest if my answer is correct
Answer:
Option B. 24 horses and 50 humans
Step-by-step explanation:
Let
x ----> the number of humans
y ----> the number of horses
Remember that
A human has one head and two legs
A horse has one head and four legs
so
----> equation A
-----> equation B
Solve the system by graphing
The solution of the system is the intersection point both graphs
The solution is the point (50,24)
see the attached figure
therefore
The number of humans is 50 and the number of horses is 24
length = area/width
l = 45/5 = 9
The length of the rectangle is 9.