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2 years ago

What is 16 times 24.I need this answer for my area model help me

Mathematics

2 answers:

USPshnik [31]2 years ago

4 0

16*24=384

You could just use an online calculator as well, but I hope this helped!

Annette [7]2 years ago

3 0

The answer to this problem is 384. Hope this helped you out

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Please answer this it’s very hard for me

Nimfa-mama [501]

Answer:

C, D, E, F

Step-by-step explanation:

Remember y=mxb?

m is slope and b is y-intercept

so y=2/7x-9

Remember that slope is RISE/RUN so for every 2 squares that you go up, you go 7 squares to the right.

Also remember that since your graph is going thru your Cartiesian Plane in quadrent 4, your y value in your ordered pairs will most probably be a negative.

Please see the image to help you viualize this.

3 0

2 years ago

A golfball is hit from the ground with an initial velocity of 200 ft/sec. The horizontal distance that the golfball will travel,

algol13

Answer:

The golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

Step-by-step explanation:

The formula from the maximum distance of a projectile with initial height h=0, is:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}$

Where $v_i$ is the initial velocity.

In the closed interval method, the first step is to find the values of the function in the critical points in the interval which is $[0, \pi/2]$ . The critical points of the function are those who make $d'(\theta)=0$ :

$d(\theta)=\frac{v_i^2\sin(2\theta)}{g}\\d'(\theta)=\frac{v_i^2\cos(2\theta)}{g}*(2)\\d'(\theta)=\frac{2v_i^2\cos(2\theta)}{g}$

$d'(\theta)=0\\\frac{2v_i^2\cos(2\theta)}{g}=0\\\cos(2\theta)=0\\2\theta=\pi/2,3\pi/2,5\pi/2,...\\\theta=\pi/4,3\pi/4,5\pi/4,...$

The critical value inside the interval is $\pi/4$ .

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\d(\pi/4)=\frac{v_i^2sin(2(\pi/4))}{g}\\d(\pi/4)=\frac{v_i^2sin(\pi/2)}{g}\\d(\pi/4)=\frac{v_i^2(1)}{g}\\d(\pi/4)=\frac{(200)^2}{32}\\d(\pi/4)=\frac{40000}{32}\\d(\pi/4)=1250ft$

The second step is to find the values of the function at the endpoints of the interval:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\\theta=0\\d(0)=\frac{v_i^2sin(2(0))}{g}\\d(0)=\frac{v_i^2(0)}{g}=0ft\\\theta=\pi/2\\d(\pi/2)=\frac{v_i^2sin(2(\pi/2))}{g}\\d(\pi/2)=\frac{v_i^2sin(\pi)}{g}\\d(\pi/2)=\frac{v_i^2(0)}{g}=0ft$

The biggest value of f is gived by $\pi/4$ , therefore $\pi/4$ is the absolute maximum.

In the context of the problem, the golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

4 0

2 years ago

Jayda is watching a movie that lasts 1 hour and 37 minutes. She has watched 52 minutes so far. How many minutes are left in the

Svetlanka [38]

Answer:

45 minutes

Step-by-step explanation:

97-52 = 45

5 0

2 years ago

Solve for x.<br> y=x-6<br> y=9<br> Simplify your answer as much as p

lukranit [14]

Step-by-step explanation:

$y + 6 = x \\ y = 9 \\ x = 9 + 6 \\ x = 15$

8 0

2 years ago

Read 2 more answers

In a particular triathlon the athletes cover 1/24 of the total distance by

pav-90 [236]

Answer:

15/8

Step-by-step explanation:

Let "d" be the total distance, that is, the distance for swimming (s), running (r) and going by bike (b).

d = s + r + b [1]

1/24 of the total distance is covered by swimming.

s = 1/24 d [2]

1/3 of the distance is covered by running.

r = 1/3 d [3]

If we replace [2] and [3] in [1], we get

d = 1/24 d + 1/3 d + b

b = d - 1/24 d - 1/3 d

b = 24/24 d - 1/24 d - 8/24 d

b = 15/24 d = 5/8 d

The ratio of the distance covered by bike to the distance covered by running is:

b/r = (5/8 d)/(1/3 d) = 15/8

5 0

2 years ago