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4 years ago

Which graph represents a linear function that has a slope of 0.5 and a y-intercept of 2?

Mathematics

2 answers:

masha68 [24]4 years ago

7 0

Answer:

The graph in the attached figure

Step-by-step explanation:

we know that

The equation of the line in slope intercept form is equal to

$y=mx+b$

where

m is the slope

b is the y-intercept

In this problem we have

$m=0.5\\b=2$

substitute

$y=0.5x+2$

The easiest way to graph a line is with a pair of points.

Find the intercepts

The y-intercept is given ----> point (0,2)

The x-intercept is the value of x when the value of y is equal to zero

For y=0

$0=0.5x+2$

$x=-4$

The x-intercept is the point (-4,0)

Plot the intercepts and join the points to graph the line

using a graphing tool

The graph in the attached figure

lapo4ka [179]4 years ago

6 0

Answer:

the answer is D .

Step-by-step explanation:

get a ps5

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From what i can see, the answer is 70

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3 years ago

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Can someone please help me with math

DaniilM [7]

Answer:

Step-by-step explanation:

they want us to find the equation in slope intercept form

which is y= mx + b

where m = slope and b = y intercept

the slope is change in y over change in x

as y goes up 1 x goes up 1 so the slope is 1 or m=1

the y intercept is at point (0,1)

so the y intercept is 1

now we add it all together and get that the equation Is

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8 0

3 years ago

A hot air balloon went from an elevation of 6,678 feet to an elevation of 3,438 feet in 48 minutes. What was its rate of descent

gregori [183]

Answer:

The rate of descent is $-67.5\frac{feet}{minute}$

Step-by-step explanation:

we know that

The formula to calculate the rate or slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

Let

x------> the time in minutes

y----> the elevation in feet

we have

$A(0,6,678)\ B(48,3,438)$

Substitute the values

$m=\frac{3,438-6,678}{48-0}$

$m=\frac{-3,240}{48}$

$m=-67.5\frac{feet}{minute}$

4 0

3 years ago

Suppose p" must approximate p with relative error at most 10-3 . Find the largest interval in which p* must lie for each value o

goblinko [34]

Answer:

$[p-|p|*10^{-3} \, , \, p+|p|* 10^-3]$

Step-by-step explanation

The relative error is the absolute error divided by the absolute value of p. for an approximation p*, the relative error is

r = |p*-p|/|p|

we want r to be at most 10⁻³, thus

|p*-p|/|p| ≤ 10⁻³

|p*-p| ≤ |p|* 10⁻³

therefore, p*-p should lie in the interval [ - |p| * 10⁻³ , |p| * 10⁻³ ], and as a consecuence, p* should be in the interval [p - |p| * 10⁻³ , p + |p| * 10⁻³ ]

8 0

3 years ago

If a/b < c/d with b > 0, d > 0, prove that a+c / b+d lies between the two fractions a/b and c/d .

Tems11 [23]

Divide through everything by b :

$\dfrac{a+c}{b+d} = \dfrac{\dfrac ab + \dfrac cb}{1 + \dfrac db}$

Since a/b < c/d, it follows that

$\dfrac{a+c}{b+d} < \dfrac{\dfrac cd+\dfrac cb}{1 + \dfrac db}$

Multiply through everything on the right side by b/d to get

$\dfrac{a+c}{b+d} < \dfrac{\dfrac{bc}{d^2}+\dfrac cd}{\dfrac bd+1} = \dfrac{\dfrac cd\left(\dfrac bd+1\right)}{\dfrac bd+1} = \dfrac cd$

and so (a + c)/(b + d) < c/d.

For the other side, you can do something similar and divide through everything by d :

$\dfrac{a+c}{b+d} = \dfrac{\dfrac ad + \dfrac cd}{\dfrac bd + 1}$

and a/b < c/d tells us that

$\dfrac{a+c}{b+d} > \dfrac{\dfrac ad + \dfrac ab}{\dfrac bd + 1}$

Then

$\dfrac{a+c}{b+d} > \dfrac{\dfrac ab + \dfrac{ad}{b^2}}{1 + \dfrac db} = \dfrac{\dfrac ab\left(1+\dfrac db\right)}{1 + \dfrac db} = \dfrac ab$

and so (a + c)/(b + d) > a/b.

Then together we get the desired inequality.

5 0

3 years ago