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3 years ago

What is the equation of this line? y=1/2x-3 y=-1/2x-3 y=-2x-3 y=2x-3

Mathematics

2 answers:

quester [9]3 years ago

6 0

Answer:

y=1/2x-3

Step-by-step explanation:

y=mx+b where m equals the slope and b equals the y-intercept. The slope is 1/2 and the y-intercept is -3. Hope this helps!

Contact [7]3 years ago

4 0

Daddy becuase I know it is becuase yeah

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Simplify: -14cd-2c^2d^2+15cd+9c^2d^2-15cd

MaRussiya [10]

7c^2d^2-14cd

Hope this helps a bunch!!!!!!!!!!!!

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3 years ago

Use the discriminant to determine how many real number solutions exist for the quadratic equation –4j2 + 3j – 28 = 0. A. 3 B. 2

Zepler [3.9K]

Answer:

C. 0

Step-by-step explanation:

–4j^2 + 3j – 28 = 0

The discriminant is b^2-4ac if >0 we have 2 real solutions

=0 we have 1 real solutions

<0 we have 2 imaginary solutions

a = -4, b =3 c = -28

b^2 -4ac

(3)^2 - 4(-4)*(-28)

9 - 16(28)

9 -448

This will be negative so we have two imaginary solutions.

Therefore we have 0 real solutions

5 0

4 years ago

Lorenzo went to the store with 20$. He bought some cans of soup for 2$ each and a gallon of milk for 3$. He had 1$ left over.

Dominik [7]

2s + 3 = 19
2s = 16
s = 8
He can buy 8 cans of soup.

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3 years ago

How many days in january

sasho [114]

There are 31 days in january

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3 years ago

Read 2 more answers

Please help I will give Brainliest please!

WITCHER [35]

Part (a)

The domain is the set of allowed x inputs of a function.

The graph shows that x = 0 is not allowed because of the vertical asymptote located here. It seems like any other x value is fine though.

<h3>Domain: set of all real numbers but $x \ne 0$ </h3>

To write this in interval notation, we can say $(-\infty, 0) \cup (0, \infty)$ which is the result of poking a hole at 0 on the real number line.

--------------

The range deals with the y values. The graph makes it seem like it stretches on forever in both up and down directions. If this is the case, then the range is the set of all real numbers.

<h3>Range: Set of all real numbers</h3>

In interval notation, we would say $(-\infty, \infty)$ which is almost identical to the interval notation of the domain, except this time of course we aren't poking at hole at 0.

=======================================================

Part (b)

<h3>The x intercepts are x = -4 and x = 4</h3>

We can compact that to the notation $x = \pm 4$

These are the locations where the blue hyperbolic curve crosses the x axis.

=======================================================

Part (c)

<h3>Answer: There aren't any horizontal asymptotes in this graph.</h3>

Reason: The presence of an oblique asymptote cancels out any potential for a horizontal asymptote.

=======================================================

Part (d)

The vertical asymptote is located at x = 0, so the equation of the vertical asymptote is naturally x = 0. Every point on the vertical dashed line has an x coordinate of zero. The y coordinate can be anything you want.

<h3>Answer: x = 0 is the vertical asymptote</h3>

=======================================================

Part (e)

The oblique or slant asymptote is the diagonal dashed line.

It goes through (0,0) and (2,6)

The equation of the line through those points is y = 3x

If you were to zoom out on the graph (if possible), then you should notice the branches of the hyperbola stretch forever upward but they slowly should approach the "fencing" that is y = 3x. The same goes for the vertical asymptote as well of course.

<h3>Answer: Oblique asymptote is y = 3x</h3>

5 0

3 years ago