Question

A rectangle measures 2 4/5 inches by 2 1/5 inches. What is its area?

Answer 1

Digram:

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 24/5 inches}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 21/5 inches}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$

Given :

• Dimensions of rectangle are $\sf\dfrac{24}{5}$ inches and $\sf\dfrac{21}{5}$.

To find:

• Area of rectangle

we know:

$\bigstar \boxed{ \sf Area \: of \: rectangle = length \times breadth}$

$\dashrightarrow \sf{}Area \: of \: rectangle = \dfrac{24}{5} \times \dfrac{21}{5}$

$\dashrightarrow \sf{}Area \: of \: rectangle = \dfrac{24 \times 21}{5 \times 5}$

$\dashrightarrow \sf{}Area \: of \: rectangle = \dfrac{504}{25}$

$\dashrightarrow \underline{ \boxed{\sf{}Area \: of \: rectangle =20.16 \: inches}}$

know more:

$\boxed{\begin {minipage}{9cm}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {minipage}}$