Im gonna hope this is a coding question.
It's parent (unit) and make children (objects)
If it's word/excel give me the multiple choice answers please.
1. Necessary backup from cloud storage to client workstation or desktop or pc.
2. Delete 30 day and one year data from cloud storage.
<u>Explanation:</u>
Purging the data is used in database where necessary backup and purging the data up to certain years. So that database is access will be faster.
At cloud storage it has very limited storage's and by increasing storage will cost more to company or organization, as best practices every 30 day the purge old data should done in cloud storage's and with necessary backup to be taken as precautionary measurement.
Once data is completed more than one year, with necessary backup delete old year data from cloud storages. Some cases old dead account where been deactivated also can deleted depends of organizations policy.
Answer:
#include <iostream>
using namespace std;
int main(){
int arr1[5], arr2[5], k = 7;
arr1 = {1,3,5,3,6}
arr2 = {1,3,2,4,4}
int reverseA2[5];
for (int x = 5; x > 0; x++){
reverseA2[5-x] = arr2[x-1];
}
for (int i = 0; i < 5; i++){
if ( arr1[i] + reverseA2[i] < k){
cout<< arr1[i] << " , "<<reverseA2[i];
}
}
}
Explanation:
The C++ source code prints a pair of values from the arr1 and reverse arr2 arrays whose sum is less than the value of the integer variable value k.
Answer:
It is not possible.
Explanation:
In this example, we need to accommodate 473 computers for six clients that are 473 IP addresses.
For this request just we have /22 IPv4 address blocks, this mean
22 red bits 11111111111111111111110000000000 <--- 10 host bits
We must increase red bits to 25, we need these 3 bits to create 6 sub red, in this case, 2^3 = 8 sub red.
Why did we ask 3 bits? Because if we ask only 2, 2^2 = 4, and we need 6 sub red.
25 red bits 11111111111111111111111110000000 7 host bits
In this case, we need more than 260 computers, but just we have 7 bits, this means.
2^7 = 128 and just one customer needs 260, for that is impossible.
