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3 years ago

How do you find the diameter of a circle with the circumference?

1 answer:

meriva3 years ago

8 0

Hello :
the circumference of a circle is P : P = <span>2π×r r : ridus
</span> P = 2π×r = π× L because : 2r = L
you can find the diameter L : L = P/π

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How many ways can 6 letters be arranged 3 at a time

ivolga24 [154]

Answer in attachment

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2 years ago

3/4 x 1/8 in simples form

Zielflug [23.3K]

Answer:

3/32

Step-by-step explanation:

To get this answer, multiply the numerators together and the denominators together

3x1=3

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3 years ago

Enter the correct answer in the box. solve the equation x2 − 16x 54 = 0 by completing the square. fill in the values of a and b

poizon [28]

The roots of the given polynomials exist $x=8+\sqrt{10}$ , and $x=8-\sqrt{10}$ .

<h3>What is the formula of the quadratic equation?</h3>

For a quadratic equation of the form $a x^{2}+b x+c=0$ the solutions are

$x_{1,2}=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Therefore by using the formula we have

$x^{2}-16 x+54=0$$

Let, a = 1, b = -16 and c = 54

Substitute the values in the above equation, and we get

$x_{1,2}=\frac{-(-16) \pm \sqrt{(-16)^{2}-4 \cdot 1 \cdot 54}}{2 \cdot 1}$$

simplifying the equation, we get

$$&x_{1,2}=\frac{-(-16) \pm 2 \sqrt{10}}{2 \cdot 1} \\$

$$&x_{1}=\frac{-(-16)+2 \sqrt{10}}{2 \cdot 1}, x_{2}=\frac{-(-16)-2 \sqrt{10}}{2 \cdot 1} \\$

$$&x=8+\sqrt{10}, x=8-\sqrt{10}$

Therefore, the roots of the given polynomials are $x=8+\sqrt{10}$ , and

$x=8-\sqrt{10}$ .

To learn more about quadratic equations refer to:

brainly.com/question/1214333

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3 0

1 year ago

Read 2 more answers

I NEED HELP!!! NOW!!!! A shape is picked at random from the group below.

evablogger [386]

Answer:

not picking a circle, not picking a square, and picking a shape that has only straight edges.

Step-by-step explanation:

All of these are 6/8, or 3/4.

7 0

3 years ago

Read 2 more answers

Solve for D, E, F, and G

Sergio039 [100]

Answer:

D=135

E=72

F=20

G=101

D: (360-90)/2

E: 45+27

F: (135-15)/6

G: 86+15

6 0

3 years ago