Answer:
28.3
Step-by-step explanation:
12/20 = 17/x
cross multiply
12x=340
divide each side by 12
x=28.3333333333.......
round it to nearest tenth
28.3
Answer:
29/112
Step-by-step explanation:
3 5/8=29/8
(29/8)/14
(29/8)(1/14)=29/112
suppose the people have weights that are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Find the probability that if a person is randomly selected, his weight will be greater than 174 pounds?
Assume that weights of people are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Mean = 177
standard deviation = 26
We find z-score using given mean and standard deviation
z = 
= 
=-0.11538
Probability (z>-0.11538) = 1 - 0.4562 (use normal distribution table)
= 0.5438
P(weight will be greater than 174 lb) = 0.5438