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krok68 [10]
2 years ago
12

Find the area of the irregular figure. plssss

Mathematics
2 answers:
Flauer [41]2 years ago
8 0

Answer:

366cm²

Step-by-step explanation:

nikdorinn [45]2 years ago
6 0

\bold{\huge{\green{\underline{ Solution }}}}

\bold{\underline{Let's \: Begin :- }}

<u>Here</u><u>, </u><u> </u><u>we </u><u>have </u><u>given </u><u>:</u><u>-</u><u> </u>

  • <u>A </u><u>rectangle </u><u>having </u><u>dimensions </u><u>14cm</u><u> </u><u>,</u><u> </u><u>2</u><u>1</u><u> </u><u>cm</u><u> </u><u>and </u><u>12cm </u>
  • <u>A </u><u>triangle </u><u>having </u><u>dimensions </u><u>16cm </u><u>and </u><u>x</u>

\bold{\underline{ We\:know\:that :- }}

\sf{\red{ Area of rectangle = L × B }}

<u>We </u><u>know </u><u>that</u><u>, </u>

The opposite sides of rectangle are equal so from above figure we can conclude that the length and breath of the rectangle are also equal that is 14cm and 21 cm

<u>Subsitute </u><u>the </u><u>required </u><u>values </u><u>in </u><u>the </u><u>above </u><u>formula </u><u>:</u><u>-</u>

\sf{ Area \:of\: rectangle = 14 × 21}

\sf{ = 294cm²}

\sf{ Thus, \: the \:area\:of \: rectangle = 294cm²}

\bold{\underline{ Now }}

We have another figure that is triangle and we have dimensions 16cm and x. x is used to denote the height of the triangle

\sf{\underline{ For\: height }}

\sf{\underline{ =  21 - 12  }}

\sf{\underline{ =  9 }}

<u>Therefore</u><u>, </u>

\sf{ Area \:of\: triangle = 1/2 × B × H}

\sf{ Area \:of\: triangle = 1/2 × 16 × 9}

\sf{ Area \:of\: triangle = 8 × 9}

\sf{ Area \:of\: triangle = 72 cm²}

\sf{ Thus, \: the \:area\:of \: triangle = 72 cm²}

\bold{\underline{ Now }}

\sf{\underline{Total \: area\: of\:irregular \: figure}}

\sf{ = 294 + 72}

\sf{ = 366 cm²}

\sf{\red{Hence,  \:The\: total\: area \:is\: 366 cm²}}

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