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Grace [21]
2 years ago
12

Please help me in this!!!!!!

Mathematics
2 answers:
TEA [102]2 years ago
4 0

Answer:

Lower (or First) Quartile = 15

Step-by-step explanation:

Alex Ar [27]2 years ago
3 0

Answer:

15 I think

Step-by-step explanation:

been a while since I did that but I think 15

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Since x=-10, plug that into the equation.

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So the ordered pair in (x,y) terms is (-10,-9).
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Write the number 6,007,200 in two different forms
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3600 dollars is placed in an account with an annual interest rate of 9%. How much will be in the account after 25 years, to the
Arlecino [84]

Answer:

31043.09

Step-by-step explanation:

Kinda feel bad for the last person who answered! They were way off but still you need to learn from your mistakes! Welp this answer is STRAIGHT OFF THE BACK from delta MATH! So this IS correct! If this helped click the stars and the heart to help fellow students, educators, etc. Understand this answer is for certain correct! I would add the steps but there is alot!

3 0
3 years ago
A machine that fills beverage cans is supposed to put 12 ounces of beverage in each can. The standard deviation of the amount in
erica [24]

Answer:

\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54

The degrees of freedom are:

df=n-1=10-1=9

Now we can calculate the p value using the alternative hypothesis:

p_v =2*P(\chi^2 >13.54)=0.279

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

Step-by-step explanation:

Assuming the following data:"12.14 12.05 12.27 11.89 12.06

12.14 12.05 12.38 11.92 12.14"

We can calculate the sample deviation with this formula:

s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

n=10 represent the sample size

\alpha=0.05 represent the confidence level  

s^2 =0.0217 represent the sample variance

\sigma^2_0 =0.12^2= 0.0144 represent the value to verify

Null and alternative hypothesis

We want to determine whether the standard deviation differs from 0.12 ounce, so the system of hypothesis would be:

Null Hypothesis: \sigma^2 = 0.0144

Alternative hypothesis: \sigma^2 \neq 0.0144

The statistic can be calculated like this;

\chi^2 =\frac{n-1}{\sigma^2_0} s^2

\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54

The degrees of freedom are:

df=n-1=10-1=9

Now we can calculate the p value using the alternative hypothesis:

p_v =2*P(\chi^2 >13.54)=0.279

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

7 0
3 years ago
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