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blsea [12.9K]
3 years ago
14

Miki has 104 nickels and 88 dimes. She wants to divide her coins into groups where each group has the same number of nickels and

the same number of dimes. What is the largest number of groups she can have?
Mathematics
2 answers:
pochemuha3 years ago
6 0

Given :

Miki has 104 nickels and 88 dimes.

She wants to divide her coins into groups where each group has the same number of nickels and the same number of dimes.

To Find :

Largest number of groups she can have .

Solution :

In the given question we need to find the largest number of groups she can have i.e we have to find the LCM of 104 and 88 .

Now , factorizing both of them , we get :

104=1\times 2\times 2\times 2\times 13

88=1\times 2\times 2\times 2\times 11

Form above , we can say that common factors are :

HCF=2\times 2\times 2=8

Therefore , the largest number of groups she can have is 8 .

Hence , this is the required solution .

Yanka [14]3 years ago
6 0

Answer:

The answer is 8 trust me

Step-by-step explanation:

I did the quiz can I get likes and brainlist

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<u><em>Answers:</em></u>

a. \frac{14}{3}=4.667 miles/day

b. 14 miles

<u><em>Explanation:</em></u>

<u>Part a:</u>

We are given that they paddled a total distance of 14 miles for 3 days. To get the distance paddled each day, we will divide the total paddled distance by the number of days

<u>This is done as follows:</u>

Distance paddled each day = \frac{14}{3}=4.667 miles/day

<u>Part b:</u>

<u>Now, we are given that:</u>

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Daily distance = \frac{1}{2}*\frac{14}{3}=\frac{7}{3} miles/day

<u>ii. They extended the trip twice as many days</u>

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<u>This means that:</u>

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