Lim x→a f(x) = 0
lim x→a g(x) = 0
lim x→a h(x) = 1
lim x→a p(x) = ∞
lim x→a q(x) = ∞
(a) lim x→a [f(x) − p(x)]
lim x→a f(x) - lim x→a p(x)
0 - ∞
-∞
(b) lim x→a [p(x) − q(x)]
lim x→a p(x) - lim x→a q(x)
∞ - ∞
0
(c) lim x→a [p(x) + q(x)]
lim x→a p(x) + lim x→a q(x)
∞ + ∞
∞
Answer:
Hour 3
4 * 2 = 8
Hour 4
8 * 2 = 16
Hour 6
32 * 2 = 64
Hour 7
64 * 2 = 128
Hour 12
2048 * 2 = 4096
Step-by-step explanation:
We are told that initially there is a bacterium that doubles every hour, so let's calculate what happens in the first 12 hours every hour.
Hour 0
one
Hour 1
1 * 2 = 2
Hour 2
2 * 2 = 4
Hour 3
4 * 2 = 8
Hour 4
8 * 2 = 16
Hour 5
16 * 2 = 32
Hour 6
32 * 2 = 64
Hour 7
64 * 2 = 128
Hour 8
128 * 2 = 256
Hour 9
256 * 2 = 512
Hour 10
512 * 2 = 1024
Hour 11
1024 * 2 = 2048
Hour 12
2048 * 2 = 4096
We can deduce that the growth of the bacteria is:
2 ^ n
where n is the # of time that has passed
Answer: Area = Length times width
Area = (3w + 7) x w
Area = 3(3 x 3 + 7) x 3 = 48 m^2
Step-by-step explanation:
Area = Length times width
Area = (3w + 7) x w
Area = 3(3 x 3 + 7) x 3 = 48 m^2
The answer to A is 4.6
The answer to B is 3.16
