Ask question

Ask question

All categories

4 years ago

5

A quadrilateral with vertices at A(4, –4), B(4, –16), C(12, –16), and D(12, –4) has been dilated with a center at the origin. Th

e image of D, point D, has coordinates (36, –12). What is the scale factor of the dilation?
1/9
1/3
3
9

2 answers:

Bess [88]4 years ago

8 0

Answer:

Scale factor of the dilation is 3

Step-by-step explanation:

Given a quadrilateral with vertices at A(4, -4), B(4, -16), C(12, -16), and D(12, -4) has been dilated with a center at the origin. The image of D i.e coordinates of D after dilation are (36,-12).

we have to find the scale factor of the dilation.

As we know if the scale factor for dilation is k the new coordinates after dilation can be calculated as

(x,y) → (kx,ky)

As image of D given i.e

D(12,-4) → D'(36,-12)

⇒ 12 → 12k i.e 12k=36 ⇒ k=3

and -4 → -4k i.e -4k=-12 ⇒ k=3

hence, scale factor of the dilation is 3

erastova [34]4 years ago

6 0

I think the answer is 3, because D(12;-4) and D' is (36;-12). Then 36/12=3, -12/-4=3
(I hope it's true)!!! :)

You might be interested in

Solve the system of equations by using substitution.<br> x+8y=-2<br> x-3y=20

zysi [14]

Answer:

(14, -2)

Step-by-step explanation:

To solve by using substitution, begin by solving for a variable in the first equation. Let's solve for x:

$x+8y=-2\\x=-2-8y$

Now we know what <em>x</em> equals. Let's substitute this into the second equation:

$x-3y=20\\(-2-8y)-3y=20$

We can then simplify:

$-2-8y-3y=20$ Given equation

$-2-11y=20$ Combine y terms

$-11y=22$ Add 2

$y=-2$ Divide by -11

So, we now know the value of y = -2.

To find the value of X, we can substitute the value of Y into one of the equations. Let's use the first one:

$x+8y=-2$

$x+8(-2)=-2$ Substitute for y

$x-16=-2$ Distribute 8

$x=14$ Add 16

So, we now know the value of x = 14.

Therefore, we know a solution to the system of equations is (14, -2).

4 0

3 years ago

Pick a expression that matches the written description Subtract a from the quotient of 6 and B

Luba_88 [7]

An expression that is equivalent to the statement Subtract a from the quotient of 6 and B is 6/b - a

<h3>How to write equivalent expression</h3>

Given statement

Subtract a from the quotient of 6 and B

The quotient of 6 and B can be written as 6/B

a subtracted from 6/B is written as

6/B - a

Therefore, the correct option equivalent to the statement is option A) 6/B - a

Learn more about equivalent expression:

brainly.com/question/2972832

3 0

2 years ago

Read 2 more answers

The diameter of a circle is 5 ft. Find the circumference to the nearest tenth(urgent)

defon

Answer:

15.71

Step-by-step explanation:

To find the radius, half the diameter because r x 2 = diameter. 5/2 = 2.5

Put in circumference formula C=2πr

c=2 x 3.14 x 2.5

c= 2 x 7.85

c=15.7

Put the value into the circle circumference formula C=2πr

5 0

3 years ago

What would this One be??

inn [45]

Answer:

the pre-image and the image are congruent

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Which table shows a proportional relationship between x and y ?

insens350 [35]

Answer:

Table C

Step-by-step explanation:

Given

Table A to D

Required

Which shows a proportional relationship

To do this, we make use of:

$k = \frac{y}{x}$

Where k is the constant of proportionality.

In table (A)

x = 2, y = 4

$k = \frac{y}{x}$

$k = \frac{4}{2}$

$k = 2$

x = 4, y = 9

$k = \frac{y}{x}$

$k = \frac{9}{4}$

$k = 2.25$

Both values of k are different. Hence, no proportional relationship

In table (B)

x = 3, y = 4

$k = \frac{y}{x}$

$k = \frac{4}{3}$

$k = 1.33$

x = 9, y = 16

$k = \frac{y}{x}$

$k = \frac{16}{9}$

$k = 1.78$

Both values of k are different. Hence, no proportional relationship

In table (C):

x = 4, y = 12

$k = \frac{y}{x}$

$k = \frac{12}{4}$

$k = 3$

x = 5, y = 15

$k = \frac{y}{x}$

$k = \frac{15}{5}$

$k = 3$

x = 6, y = 18

$k = \frac{y}{x}$

$k = \frac{18}{6}$

$k = 3$

This shows a proportional relationship because all values of k are the same for this table

7 0

3 years ago