The diagram shows a cone and its axis of rotation. If a plane passes through the axis of rotation, which type of cross section w
ill be formed?
A: a circle
B: an isosceles triangle
C: a parabola
D: an oval
A: a circle
B: an isosceles triangle
C: a parabola
D: an oval
2 answers:
Answer: The answer is (B). An isosceles triangle.
Step-by-step explanation: In the given figure, a cone and its axis of rotation is shown. We are to select the type of cross-section that will be formed if the plane passes through the axis of rotation.
See the attached figure, if a plane passes through the axis of rotation of the cone, then the resultant cross-section will be a triangle with one vertex as the vertex of the cone, i.e., A. And also, the two sides of the triangle through the vertex A will be equal.
The cross-section is also shown in the attached figure and it will be an isosceles triangle ABC, where AB = AC.
Thus, the correct option is (B) an isosceles triangle.
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All expressions whose sum represents the same vector as (r + s) + t. is Option b,c,e
<h3>What are the expressions that equals (r + s) + t. ?</h3>Where
r= (2,3)
s= (5,-3)
t= (-8,6)
Generally, the equation for statement is mathematically given as
(7,0)+(-8,6) ,(2,3)+(-3,3) and (-6,9)+(5,-3) are equal to (r+s)+t
Therefore
x=(2,3)+(5,-3)
x=(7,0)
Now we can calculate (r+s)+t as
(7,0)+(-8,6)
(7-8,0+6)
(-1,6)
For (b)
x=(7,0)+(-8,6)
x=(-1,6)
in this scenario x expressions is equal to (r+s)+t
For (c)
x=(2,3)+(-3,3,)
x=(-1,6)
in this scenario x expressions is equal to (r+s)+t
For (e)
x=(-1,6)
in this scenario x expressions is equal to (r+s)+t
In conclusion, all expressions whose sum represents the same vector as (r + s) + t. is b,c,e
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Answer:
Approximately , assuming that
.
Step-by-step explanation:
Initial kinetic energy of the sled and its passenger:
.
Weight of the slide:
.
Normal force between the sled and the slope:
.
Calculate the kinetic friction between the sled and the slope:
.
Assume that the sled and its passenger has reached a height of meters relative to the base of the slope.
Gain in gravitational potential energy:
.
Distance travelled along the slope:
.
The energy lost to friction (same as the opposite of the amount of work that friction did on this sled) would be:
.
In other words, the sled and its passenger would have lost (approximately) of energy when it is at a height of
.
The initial amount of energy that the sled and its passenger possessed was . All that much energy would have been converted when the sled is at its maximum height. Therefore, when
is the maximum height of the sled, the following equation would hold.
.
Solve for :
.
.
Therefore, the maximum height that this sled would reach would be approximately .