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3 years ago

What does the 2 represent in 12.789

Mathematics

2 answers:

oksian1 [2.3K]3 years ago

8 0

It is a whole number in the one digits place
:)

11111nata11111 [884]3 years ago

7 0

(Tens digit)(Ones digit) . (tenths digit)(hundredths digit)(thousandths digit)
12.789
2 = (ones digit)

Hope this helps!

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Please help out and if you know help me show work ??

Ghella [55]

Answer: 14

<u>Step-by-step explanation:</u>

Consecutive even numbers would be {2, 4, 6, 8, 10, ...}

Let x represent the smallest number, then x + 2 is the middle number and x + 4 is the largest number.

1st number: x

2nd number: x + 2

3rd number: x + 4

1st number + 2nd number + 3rd number = Sum

(x) + (x + 2) + (x + 4) = 48

3x + 6 = 48

3x = 42

x = 14

1st number: x ⇒ x = 14

2nd number: x + 2 ⇒ 14 + 2 = 16

3rd number: x + 4 ⇒ 14 + 4 = 18

<u>Check:</u>

14 + 16 + 18 = 48 $\checkmark$

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2 years ago

Which of the following is not an itemized deduction?

Verdich [7]

Answer:

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6 0

2 years ago

Read 2 more answers

Which of the following expresion is equivalint to 2d(3d-4)

Alex

Answer:

6d^2 - 8d

Step-by-step explanation:

Multiply 2d to the other two monomials

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3 years ago

pranav's school is selling tickets to a play. On the first day of tickets sales the school sold 8 adult tickets and 4 child tick

viva [34]

Adult tickets are $8 and child tickets are $4

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3 years ago

Find parametric equations for the path of a particle that moves along the circle x2 + (y − 1)2 = 16 in the manner described. (En

ArbitrLikvidat [17]

Answer:

a) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ , b) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ , c) $x = 4\cdot \cos \left(t+\frac{\pi}{2} \right)$ , $y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right)$ .

Step-by-step explanation:

The equation of the circle is:

$x^{2} + (y-1)^{2} = 16$

After some algebraic and trigonometric handling:

$\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = 1$

$\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = \cos^{2} t + \sin^{2} t$

Where:

$\frac{x}{4} = \cos t$

$\frac{y-1}{4} = \sin t$

Finally,

$x = 4\cdot \cos t$

$y = 1 + 4\cdot \sin t$

a) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ .

b) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ .

c) $x = 4\cdot \cos t''$ , $y = 1 + 4\cdot \sin t''$

Where:

$4\cdot \cos t' = 0$

$1 + 4\cdot \sin t' = 5$

The solution is $t' = \frac{\pi}{2}$

The parametric equations are:

$x = 4\cdot \cos \left(t+\frac{\pi}{2} \right)$

$y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right)$

7 0

3 years ago