Answer:
Part a) The quadratic function is 
Part b) The value of x is
Part c) The photo and frame together are
wide
Step-by-step explanation:
Part a) Write a quadratic function to find the distance from the edge of the photo to the edge of the frame
Let
x----> the distance from the edge of the photo to the edge of the frame
we know that

Part b) What is the value of x?
Solve the quadratic equation 
The formula to solve a quadratic equation of the form
is equal to
in this problem
we have

so
substitute in the formula

-----> the solution
Part c) How wide are the photo and frame together?

Answer:

Step-by-step explanation:
Given


Required
Eliminate a
Multiply the first equation by -4

Add to the second equation

Solve brackets

Open bracket


At this point, a has been eliminated;
From the list of given options, the option that answers the question is 
If x < - 2 and x ∈ { - 5, - 2.6, - 2, - 0.8, 1, 1.5 }
- 5 < - 2 and - 2.6 < - 2
The solution set is:
A ) { - 5 , - 2.6 }
440 yards x 20 = 8800 yards.
8800 yards is equal to 5 miles.
Answer:
389 feets apart
Step-by-step explanation:
Given that:
Building A
Height = 400feets
Angle of elevation = 70°
Building B:
Height = 300 feets
Angle of elevation = 52°
Distance from the foot of building A to where Jonny is standing = x (see attached picture)
Using trigonometry :
Tanθ = opposite / Adjacent
Tan 70 = 400/ x
2.7474774x = 400
x = 145.58809 feets
Distance from the foot of building B to where Jonny is standing = y (see attached picture)
Using trigonometry :
Tanθ = opposite / Adjacent
Tan 52 = 300/ y
1.2799416y = 300
y = 145.59
y = 234.38568 feets
x + y = distance between the two buildings
(145.58809 + 234.38568) feets
= 379.97377
= 380 feets apart