Given segment AC and point B that lies on AC, if AB = 9 and BC= 49, find AC
1 answer:
Answer:
58
Step-by-step explanation:
Let's draw this out (see attachment).
We know that since B lies on AC, we have the points in order from left to right: A, B, C.
AB = 9, which is the left portion. BC = 49, which is the right portion. Then AC is simply the sum:
AC = AB + BC = 9 + 49 = 58
The answer is thus 58.
<em>~ an aesthetics lover</em>
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Answer:
Solution: (3, 2)
Step-by-step explanation:
It's easier to graph when the equation of the lines are in their slope-intercept form, y = mx + b.
<u>x - 3y = -3</u>
-3y = -x - 3
Divide both sides by -3:
y = 1/3x + 1
where slope = 1/3
y-intercept = 1
<u>x + y = 5</u>
Subtract x from both sides to isolate y:
x - x + y = - x + 5
y = -x + 5
where slope = -1
y-intercept, 5
I started by graphing the y-intercepts of each line. Then, I used the slope of each linear equation (rise over run) to plot the next points on the graph. In the attached screenshot of the graph, <u>x - 3y = -3</u> is the blue line, while <u>x + y = 5</u> is the green line. Their intersection occurs at point, (3, 2).
Therefore, the solution is (3, 2).
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Answer:
57/4
Step-by-step explanation:
