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2 years ago

What is (5+3)+7=5+(3+7) is it Associative, Identity, Commutative or Substitution?

Mathematics

1 answer:

timama [110]2 years ago

4 0

Answer:

Associative

Step-by-step explanation:

The associative property of addition states that you can add numbers however they are grouped inside parentheses.

It doesn't matter where you put the parentheses. You will always get the same answer.

For example,

$\begin{array}{rcl}(5 + 3) + 7 & = & 5 + (3 + 7)\\8 + 7& = & 5 + 10\\15 & = & 15\\\end{array}$

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15m+m+2 <br> I need help on combining like terms

Mice21 [21]

Answer:

its 16m+2

Step-by-step explanation:

you add m and 15 m because they have the same variable.

then you put the two right next to it

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3 years ago

Which is the area of a parallelogram with a base of 13 centimeters and a height of 3 centimeters?

GREYUIT [131]

He ANWSER I got would be c idk if this is right or not I honk it might be

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2 years ago

Please Solve This For Me If You Can y(2.5+7)+y-2

Law Incorporation [45]

Answer: 10.5y-2

Hope this helps!

4 0

2 years ago

Read 2 more answers

A fish store received a shipment of 246 goldfish. The owner of the store arranged the fish into small tanks of 8 fish per tank.

saw5 [17]

Answer:

he would need 31 tanks

30 tanks would hold 240 fish with 6 left over

Step-by-step explanation:

246/8= 30.75

30*8 = 240

6 0

3 years ago

Read 2 more answers

P(x)=x^3+2x^2-4x-8 how do you factor this polynomial function

Wewaii [24]

<h2>Steps:</h2>

So for this, I will be factoring by grouping. Firstly, factor x³ + 2x² and -4x - 8 separately. Make sure that they have the same quantity inside of the parentheses:

$p(x)=x^2(x+2)-4(x+2)$

Now we can rewrite it as:

$p(x)=(x^2-4)(x+2)$

However, we aren't finished factoring yet. The first factor, x² - 4, can be factored further using the difference of squares. The difference of squares goes by the formula here: $x^2-y^2=(x+y)(x-y)$ . In this case:

$x^2-4=(x+2)(x-2)\\p(x)=(x+2)(x-2)(x+2)$

<h2>Answer:</h2>

<u>In short, the answer is $p(x)=(x+2)(x-2)(x+2)\ \textsf{OR}\ p(x)=(x-2)(x+2)^2$ </u>

3 0

2 years ago