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2 years ago

POSSIBLE POINTS 6

Mathematics

1 answer:

yan [13]2 years ago

3 0

Answer:

D 60

Step-by-step explanation:

f(5)=35

f(6)=40

f(7)=45

f(8)=50

f(9)=55

f(10)=60

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A pack of 6 batteries of the same type cost ?2.79 . By calculating the price per battery,determine if this is better value.You m

MissTica

Answer:

The full question is attached in the picture below.

The better price for the battery is given with the 6 pack.

(£ 0.47 per battery)

Step-by-step explanation:

If 8 batteries cost £ 3.99

This means that one battery is equal to

£3.99/8 = £ 0.49875 ≈ £ 0.50 per battery

The pack of 6 batteries costs £ 2.79

This means that one battery is equal to

£2.79/6 = £ 0.465 ≈ £ 0.47 per battery

Then, we can conclude than the 6 pack gives us a better price per battery

7 0

3 years ago

How to find (c,d,e)<br>Please do a step by step working.Thank you.

Natasha2012 [34]

(a)
The inverse is when you swap the variables and solve for y.
g(t) = 2t - 1 (Note: g(t) represents y)
rewrite as: y = 2t - 1
swap the variables: t = 2y - 1
solve for y: t + 1 = 2y
   $\frac{t + 1}{2}$ = y
Answer for (a): $g^{-1}(t)$ = $\frac{t + 1}{2}$

(b)
Same steps as part (a) above:
h(t) = 4t + 3
rewrite as: y = 4t + 3
swap the variables: t = 4y + 3
solve for y: $y =\frac{t - 3}{4}$

Answer for (b): $h^{-1}(t)$ = $\frac{t - 3}{4}$

(c)
$g^{-1} ( h^{-1}(t)) = g^{-1} (\frac{t - 3}{4})$
replace all t's in the $g^{-1}(t)$ equation with $\frac{t - 3}{4}$
$g^{-1} (\frac{t - 3}{4})$ = $\frac{ \frac{t-3}{4} + 1}{2}$
= $\frac{ \frac{t-3}{4} + \frac{4}{4}}{2}$ = $\frac{ \frac{t - 3 + 4}{4}}{2}$ = $\frac{ \frac{t + 1}{4}}{2} = \frac{t + 1}{8}$
Answer for (c): $g^{-1} ( h^{-1}(t))$ = $\frac{t + 1}{8}$

(d)
h(g(t)) = h(2t - 1) = 4(2t - 1) + 3 = 8t - 4 + 3 = 8t - 1
Answer for (d): h(g(t)) = 8t - 1

(e)
h(g(t)) = 8t - 1
   y = 8 t - 1
   t = 8y - 1
t + 1 = 8y
$\frac{t + 1}{8}$ = y
Answer for (e): inverse of h(g(t)) = $\frac{t + 1}{8}$

8 0

3 years ago

e-lub [12.9K]

Hope this helps
G=4.

3 0

2 years ago

Professor Halen teaches a College Mathematics class. The scores on the midterm exam are normally distributed with a mean of 72.3

lbvjy [14]

Answer:

14.63% probability that a student scores between 82 and 90

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 72.3, \sigma = 8.9$