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Darya [45]
3 years ago
14

Write cos (19°) in terms of sine​

Mathematics
1 answer:
seraphim [82]3 years ago
8 0

Answer:

sin(71°)

Step-by-step explanation:

Sine lags behind cosine by 90°

In other word, cos(∅) = sin(90° - ∅)

cos(19°) = sin(90° - 19°)

= sin(71°)

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Alexandria,a car dealer,earns 40% commission of her luxury vehicles sales. Last year,her sales were $480,000. What was the total
Oxana [17]

Answer:

$12,000,000

Step-by-step explanation:

To find her commission, create a proportion.

\frac{40}{100}=\frac{480000}{x}

To solve use cross multiplication.

40(x) = 100(480000)

40x = 48000000

x= 12,000,000

3 0
3 years ago
Read 2 more answers
Write a quadratic equation to represent a function with the vertex (-4, 1)
pishuonlain [190]

Answer:

y=a(x+4)^2 +1, for a real number a hat is different of 0.

Step-by-step explanation:

If we know only the vertex, there are many quandratic equations.

* Result: Vertex (m,n), the quadratic equation is y= a(x-m)^2 + n for a real number a that is different of 0.

Here, the vertex (-4,1), we have the equation: y=a(x+4)^2 +1, for a real number a hat is different of 0.

Hope you understand.

6 0
3 years ago
Solve for y: 7/9y = 42
iren2701 [21]
I answered on paper hope that is alright with you. I just find it easier for math problems. That slash means two numbers cancel each other out. What's in the box is the answer and the proof that it's right is underneath.

4 0
3 years ago
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What is the value of c such that the line y=2x+3 is tangent to the parabola y=cx^2
satela [25.4K]

The value of c such that the line y = 2\cdot x + 3 is tangent to the parabola y = c\cdot x^{2} is -\frac{1}{3}.

If y = 2\cdot x + 3 is a line <em>tangent</em> to the parabola y = c\cdot x^{2}, then we must observe the following condition, that is, the slope of the line is equal to the <em>first</em> derivative of the parabola:

2\cdot c \cdot x = 2 (1)

Then, we have the following system of equations:

y = 2\cdot x + 3 (1)

y = c\cdot x^{2} (2)

c\cdot x = 1 (3)

Whose solution is shown below:

By (3):

c =\frac{1}{x}

(3) in (2):

y = x (4)

(4) in (1):

y = -3

x = -3

c = -\frac{1}{3}

The value of c such that the line y = 2\cdot x + 3 is tangent to the parabola y = c\cdot x^{2} is -\frac{1}{3}.

We kindly invite to check this question on tangent lines: brainly.com/question/13424370

3 0
2 years ago
Solve for q<br> (Please show all work thank you:))
Masja [62]

Answer:

q = ±  \frac{5}{4\sqrt{p} }

Step-by-step explanation:

We are to solve for q in:

16pq² = 25

q² = \frac{25}{16p}

\sqrt{q^2} = ±\sqrt{\frac{25}{16p} } = ± \frac{5}{4\sqrt{p} }

5 0
2 years ago
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