All categories

3 years ago

What are the partial products of 563 x 410

1 answer:

7 0

563 x 410 = 563(400 + 10) I think what they mean by partial products is 563 x 400 and 563 x 10. then you can sum the partial products to get the product of 410 x 563

You might be interested in

PLS WILL MARK BRAINLIEST DUE TODAY!!!!! Noya needs to determine the number of books that will fit into a box. If the box has a l

bonufazy [111]

Answer:

18 divided by 2/9, or 18/(2/9) (Is this what the first option was meant to say?)

Step-by-step explanation:

18 inches is the amount of space that needs to be filled, or divided up into sections to see how many things can fit.

2/9 is the width of the thing that you need to see how many fit, meaning it's the thing you're dividing by.

Combined, this means your expression is 18 divided by 2/9, or 18/(2/9). I think this is what your first option was meant to say, because if it is what it says, then the first and second option would be the exact same wrong thing.

You DON'T multiply, because if you think about easy numbers, an inch thick book should have 18 fit, and a half-inch thick book should have double that fit. As you get a smaller book, the number that fit increase, which can't happen with multiplication.

You also don't start with 2/9 because that's the width of the book. You're not trying to see how many boxes can fit into each book; that'd be ridiculous.

4 0

3 years ago

How high up on a wall will a 20-foot ladder touch if the foot of the ladder is placed

Alika [10]

Step-by-step explanation:

by using the pythagoras theorem,

the height of the ladder touching the wall =

√(20²- 4²)

=√ (400-16)

=√384

= 8√6 feet

or 19.6 feet

4 0

3 years ago

Read 2 more answers

-8k + 6 = -10k + 10 SOMEONE HELP QUICKKKK

Amiraneli [1.4K]

Answer:

k = 2

Step-by-step explanation:

-8k + 6 = -10k + 10

-8k = -10k +4

2k = +4

2k / 2 = 4 / 2

k = 2

3 0

3 years ago

Read 2 more answers

Sin cos tangent..... proving equal Ether a or b

Triss [41]

I believe the answer is A

8 0

4 years ago

The lower supports are and the area of the two supports is square meters. The upper arch can be decomposed as one semicircle wit

Galina-37 [17]

Answer:

The lower supports are Congruent Rectangles and the area of the two supports is 24 square meters.

The upper arch can be decomposed as one semicircle with radius 6 meters minus a semicircle with radius 3 meters.

The area of the archway is (13.5 π + 24) square meters.

Step-by-step explanation:

See attachment for the firgure,

In order to determine the area of archway = The area of upper support + area of lower support.

As given, the lower support are two congruent rectangles consists of dimension 3 m × 4 m

Therefore, the area of lower support can be written as,

The area of lower support = 3 × 4 + 3 × 4 = 12 + 12 = 24 square m.

Now, the upper support arch can be decomposed as the two concentric semi circles having radius 3 m and 6 m,

Hence, the area of the upper support = Area of semi circle having radius i.e 6 m - Area of semi circle having radius i.e 3 m

=> π6²/2 - π3²/2= 27π/2= 13.5π square m

Therefore, the area of the archway = (13.5 π + 24) square meters

4 0

3 years ago